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kow [346]
3 years ago
9

Consider the two functions given below.

Mathematics
2 answers:
g100num [7]3 years ago
5 0

Answer:

Option A is the correct answer.

Step-by-step explanation:

y intercept means x value is 0.

f(0) = 3 x 0 + 4 = 4

g(0)=2^0-1=1-1=0

We need same y intercepts

 That is f(0) = g(0)

           4 + a = 0 + b

Checking all the options

a) f(x) - 3 and g(x) + 1

          4 - 3 and 0 + 1

              1 and 1

    Option A is correct.

b) f(x) + 4 and g(x) - 1

          4 + 4 and 0 - 1

              8 and -1

    Option B is wrong.

c) f(x) - 2 and g(x) + 1

          4 - 2 and 0 + 1

              2 and 1

    Option C is wrong.

d) f(x) + 3 and g(x) - 6

          4 + 3 and 0 - 6

              7 and -6

    Option D is wrong.

So, Option A is the correct answer.

mestny [16]3 years ago
3 0
This means which transformation makes the same answer at x = 0

f(x) = 3x + 4
g(x) = {2}^{x}  - 1

f(0) = 4
g(0) = 1 - 1 = 0

Which transformation makes 4 = 0?

4 + x = 0 + y

4 - 3 =0 + 1

1 = 1

Option 1 is your answer
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Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2
iren2701 [21]
Hello there, hope I can help!

I assume you mean L\left\{\frac{ekt+e-kt}{2}\right\}
With that, let's begin

\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \  L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}

\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}
\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b
L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}
\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}

L\left\{t\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \  L\left\{t\right\}=\frac{1}{s^2}

L\left\{\frac{e}{2}\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \  L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \  \frac{e}{2s}

\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}

\frac{ek}{2}\cdot \frac{1}{s^2}  \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{ek\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{ek}{2s^2}

\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{k\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{k}{2s^2}

\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}

Hope this helps!
3 0
4 years ago
UT bisects WV. WV = ? <br><br> A. SV<br><br> B. 2(SV)<br><br> C. UT<br><br> D. none of the above
ValentinkaMS [17]
2(sv) is the answer for the question
4 0
3 years ago
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pentagon [3]
Answer: Should be X= 1/15
4 0
3 years ago
Help me plz it’s due today
Serggg [28]

Answer:

A

Step-by-step explanation: Your salary will be greater than or equal to $46,000.

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3 years ago
Read 2 more answers
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Free_Kalibri [48]

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