That’s a hard one use Brainly to find the answer
Answer:
A graph that has an axis of symmetry at x = 3 would be x^2 -6x + 12
Step-by-step explanation:
In order to find a graph that has an axis of symmetry at 3, use the equation for the axis of symmetry of a quadratic.
x = -b/2a
In this equation, a is the coefficient of x^2 and b is the coefficient of x. So, if we use 3 as x and we choose a random number to be a (1), we can solve for the b.
3 = -b/2(1)
3 = -b/2
6 = -b
b = -6
Now that we have this, we can put those two numbers as coefficients. The constant at the end can be anything.
multiply the length and with by the scale factor:
24 x 4/3 = 32 feet
20 x 4/3 = 26 2/3 feet
Area is length x width:
32 x 26 2/3 = 853 1/3 square feet.
F(x) = -34
Okx) = 2x
Both are correct
Hope this helps
FORMULA:
AREA= AC x h
----------------------
2
PERIMETER= AB+BC+CA
AREA = SQUAREROOT
S(S-AB)(S-BC)(A-CA)
S= AB+BC+CA= P
----------------- -----
2 2
FOR THE COMPLETE SOLUTION PLEASE SEE THE PICTURE. THANKS.