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3 years ago

Simplify . 3 sqrt 10 + 7 sqrt 15 - 6 sqrt 10 -4 sqrt 15

1 answer:

6 0

Take the like terms of the equation.

$3 \sqrt{10} - 6 \sqrt{10}$

$7 \sqrt{15} - 4 \sqrt{15}$

Subtract those like terms together.

$3 \sqrt{10} - 6 \sqrt{10} = -3 \sqrt{10}$

$7 \sqrt{15} - 4 \sqrt{15} = 3 \sqrt{15}$

The simplified form of this equation is $-3 \sqrt{10} + 3 \sqrt{15}$ .

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Factor. 49x^2−36y^2 Enter your answer in the boxes.

wel

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2 years ago

Let u = (1, 2 -2), v= (2, 1, 3) and w = j + 4k. a) Find cos theta, where theta is the angle in degrees between u and w.

vodka [1.7K]

Answer: The value of cos theta is -0.352.

Step-by-step explanation:

Since we have given that

$\vec{u}=1\hat{i}+2\hat{j}-2\hat{k}\and\\\\\vec{w}=\hat{j}+4\hat{k}$

We need to find the cos theta between u and w.

As we know the formula for angle between two vectors.

$\cos\ \theta=\dfrac{\vec{u}.\vec{w}}{\mid u\mid \mid w\mid}$

So, it becomes,

$\cos \theta=\dfrac{2-8}{\sqrt{1^2+2^2+(-2)^2}\sqrt{1^2+4^2}}\\\\\cos \theta=\dfrac{-6}{\sqrt{17}\sqrt{17}}=\dfrac{-6}{17}=-0.352\\\\\theta=\cos^{-1}(\dfrac{-6}{17})=110.66^\circ$

Hence, the value of cos theta is -0.352.

8 0

3 years ago

How to find the missing lengths of a partelogram

Levart [38]

Answer:

Below.

Step-by-step explanation:

The area = the height (h) times the base.

So Q2:

21 = h * 7

h = 21/7 = 3

55 = b * 5

b = 11.

18.75 = h * 7.5

h = 18.75 / 7.5

= 2.5.

6 0

2 years ago

I need help with this ASAP

SOVA2 [1]

Answer:

Step-by-step explanation:

1 and 2 are linear pairs

1 and 3 are verticle

4 and 5 are adjacent

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3 years ago

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Jlenok [28]

Answer:

I think the answer is 10 sq cm

Step-by-step explanation:

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2 years ago

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