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3 years ago

5

Jordan and her family enter a race around a track. Jordan take 10 minutes to run a lap, her sister 12 minutes and Katie 20 minut

es. If they race together for 60 minutes how many times will they meet at the starting line together during the race

1 answer:

Nutka1998 [239]3 years ago

3 0

They will be finished at 6:56

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Karo-lina-s [1.5K]

B and D

Step-by-step explanation:

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Alicia drove 265 miles in 5 hours What is the average rate that she traveled 49 miles per hour 51 miles per hour 53 miles per ho

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3 years ago

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Find the inverse of {(4, -1), (3, -2), (6, 9), (8, 5)}.

katen-ka-za [31]

Answer:

A∣=3(8−7)+1(−2−4)=3−6=−3

co-factor matrix =

⎣

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⎢

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⎥

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6 0

3 years ago

Please help it’s done tonight and i need a answer because i can’t figure it out:( pls help!

Darya [45]

Answer:

569,186,434

Step-by-step explanation:

hope this helps

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5 0

3 years ago

A box contains 15 resistors. twelve of them are labelled 50ω and the other three are labeled 100ω. what is the probability that

Igoryamba

Answer : P(second resistor is 100ω , given that the first resistor is 50ω) is given by

$\frac{1}{5}$

Explanation :

Since we have given that

Total number of resistors =15

Number of resistors labelled with 50ω = 12

Number of resistors labelled with 100ω =3

Let A: Event getting resistor with 50ω

B: Event getting resistor with 100ω

Since A and B are independent events .

So,

$P(A\cap B)=P(A).P(B)$

Now, According to question , we can get that

$P(A)= \frac{12}{15}=\frac{4}{5}\\\\P(B)=\frac{3}{15}=\frac{1}{5}$

So,

$P(A\cap B)=P(A).P(B)\\\\P(A\cap B)=\frac{4}{5}\times \frac{1}{5}\\\\P(A\cap B)=\frac{4}{25}$

So, by using the conditional probability , which state that

$P(B\mid A)=\frac{P(A\cap B)}{P(A)}$

$P(B\mid A)=\frac{\frac{4}{25}}{\frac{4}{5}}\\\\P(B\mid A)=\frac{5}{25}\\\\P(B\mid A)=\frac{1}{5}$

So, P(second resistor is 100ω , given that the first resistor is 50ω) is given by

$\frac{1}{5}$

4 0

3 years ago