The unit price is $1.23 (I think!!)
Two Answers: Angle 1, Angle 4
Adjacent angles share a common segment, line, or ray. Think of two adjacent rooms sharing a common wall.
To find distance, subtract the largest number from smaller
41 - (-7)
41 + 7 = 48
the distance is 48
hope this helps
First of all, we can observe that
![x^2-6x+9 = (x-3)^2](https://tex.z-dn.net/?f=x%5E2-6x%2B9%20%3D%20%28x-3%29%5E2)
So the expression becomes
![\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%5E2-4%7D%7B%5Csqrt%7B%28x-3%29%5E2%7D%7D%20%3D%20%5Cdfrac%7Bx%5E2-4%7D%7B%7Cx-3%7C%7D)
This means that the expression is defined for every ![x\neq 3](https://tex.z-dn.net/?f=x%5Cneq%203)
Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask
![x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2](https://tex.z-dn.net/?f=x%5E2-4%20%5Cgeq%200%20%5Ciff%20x%5Cleq%20-2%20%5Clor%20x%5Cgeq%202)
Since we can't accept 3 as an answer, the actual solution set is
![(-\infty,-2] \cup [2,3) \cup (3,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C-2%5D%20%5Ccup%20%5B2%2C3%29%20%5Ccup%20%283%2C%5Cinfty%29)
Answer:
terminating
Step-by-step explanation:
if the given fraction is terminating then prime factors of denominator should be 2^n x 5^m where m and n are whole number
5=1x5=2^0x5^1
so it is of form 2^nx5^m