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3 years ago

Jose invested $5000 into a fund with an interest rate of 4.8%.

Mathematics

2 answers:

Ann [662]3 years ago

7 0

He will earn $480 after 2 years

zubka84 [21]3 years ago

4 0

It would be $480 because if $240 is 4.8% of 5000 just add another $240Hope that helped

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If the perimeter of a rectangular picture frame must be less that 200 in, and the width is 36 in. what must the height H of the

fgiga [73]

Answer:

w = width

h = height

2(w+h) < 200

w + h < 100

since w = 36, then

36 + h < 100

h < 100 - 36

h < 64

Step-by-step explanation:

The perimeter of the rectangular picture frame can be calculated by the equation,

2h + 2w = P

where h and w are height and width , respectively. Substituting the known values and the condition for the inequality,

2h + 2(36 in) < 200

The inequality gives h as,

h < 64

Thus, the answer is letter A.

7 0

3 years ago

Figure B is a scaled copy of Figure A.

Mama L [17]

Answer:

4:1

Step-by-step explanation:

Corresponding sides...

4:1

4.4:1.1

4:1

6:1.5

simplify any of these or all to get

4:1

3 0

3 years ago

I need help with angles again.

zaharov [31]

Answer:

119 degrees

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The average daily volume of a computer stock in 2011 was μ=35.1 million shares, according to a reliable source. A stock analyst

alexandr1967 [171]

Answer:

The 95% confidence interval is ( 27.126 , 34.674)

Step-by-step explanation:

Given

The t critical value at 0.05 level = 2.023 for the df = 39

Confidence interval = 95%

Mean

$\bar{x} - t * \frac{s}{\sqrt{n} } < \mu < \bar{x} + t * \frac{s}{\sqrt{n} }$

Substituting the given values we get -

$\30.9 - 2.023 * \frac{11.8}{\sqrt{40} } < \mu < \30.9 + 2.023 * \frac{11.8}{\sqrt{40} }\\27.126 < \mu < 34.674$

Hence, the 95% confidence interval is

( 27.126 , 34.674)

4 0

3 years ago

Rationalize the denominator<br><br> 11/Square root of 5 - square root of 6

olasank [31]

Answer:

$-11\sqrt{5}-11\sqrt{6}$

Step-by-step explanation:

The given radical expression is;

$\frac{11}{\sqrt{5}-\sqrt{6}}$

We multiply both the numerator and the denominator by the conjugate of

$\sqrt{5}-\sqrt{6}$ which is $\sqrt{5}+\sqrt{6}$

$\frac{11(\sqrt{5}+\sqrt{6})}{(\sqrt{5}-\sqrt{6})(\sqrt{5}+\sqrt{6})}$

The denominator is now difference of two squares;

$\frac{11(\sqrt{5}+\sqrt{6})}{(\sqrt{5})^2-(\sqrt{6})^2}$

Simplify:

$\frac{11(\sqrt{5}+\sqrt{6})}{5-6}$

$\frac{11(\sqrt{5}+\sqrt{6})}{-1}$

$-11(\sqrt{5}+\sqrt{6})$

$-11\sqrt{5}-11\sqrt{6}$

8 0

3 years ago