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Mathematics

1 answer:

Ede4ka [16]3 years ago

8 0

Answer:

<u>Option B. Side YZ is the same length as side Y'X'.</u>

Step-by-step explanation:

XYZ is reflected across the y-axis and then translated down 6 units to form X'Y'Z'.

So, X' is the image of point X

Y' is the image of point Y

Z' is the image of point Z

And ΔXYZ ≅ ΔX'YΔ'Z'

And the corresponding length are congruent

We will check the options:

A. X has the same measure as X'. ⇒ True

B. Side YZ is the same length as side Y'X'. ⇒ Wrong

Because YZ will be translated to Y'Z'

C. Z has the same measure as Z'. ⇒ True

D. Side XZ is the same length as side X'Z'. ⇒ True

<u>So, The answer is option B. Side YZ is the same length as side Y'X'.</u>

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3 years ago

Select the correct answer from each drop-down menu.

mr_godi [17]

Answer:

correct option for first blank is 5/4 and for second blank is $\frac{ 3i\sqrt{7}}{4}$

i.e m= $\frac{5}{4}\pm\frac{ 3i\sqrt{7}}{4}$

Step-by-step explanation:

The given equation

$m^2 - \frac {5m}{2} = \frac{-11}{2}$

and we have to find m= ______ ± ________

We can use quadratic formula to solve this question.

The above equation can be written as: $m^2 - \frac {5m}{2} + \frac{11}{2} = 0$

and the formula used will be:

$m= \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Putting values of a= 1, b= -5/2 and c= 11/2 and solving we get: $m=\frac{-\frac{-5}{2}\pm\sqrt{{(\frac{-5}{2})}^2-4(1)(\frac{11}{2})}}{2(1)}\\\\m=\frac{\frac{5}{2}\pm\sqrt{(\frac{25}{4})-22}}{2}\\m=\frac{\frac{5}{2}\pm\sqrt{(\frac{-63}{4})}}{2}\\m= \frac{\frac{5}{2}}{2}\pm\frac{\sqrt{(\frac{-63}{4})}}{2}\\m= \frac{5}{4}\pm\frac{\sqrt{-63}}{4}$

Since there is - sign inside the √ so $\sqrt{-1}$ is equal to i and we have to divide $\sqrt{63}$ into its multiples such that the square root of one multiple is whole no so,