Answer: 11/20
55/100 simplified is 11/20
Answer:
0.048 is the probability that more than 950 message arrive in one minute.
Step-by-step explanation:
We are given the following information in the question:
The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.
Let X be the number of messages arriving at a multiplexer.
Mean = 15
For poison distribution,
Mean = Variance = 15

From central limit theorem, we have:
where n is the sample size.
Here, n = 1 minute = 60 seconds
P(x > 950)
Calculation the value from standard normal z table, we have,

0.048 is the probability that more than 950 message arrive in one minute.
Answer:
The answer is 10y + 48.
Step-by-step explanation:
First you have to get rid of brackets by expanding :

Next you have to collect like-terms :

Answer:
The percent of change is 44.7%
Step-by-step explanation:
Given that:
38 staples to 55 staples
As the number of staples are increased, therefore, the percent will also increase.
Difference = 55 - 38 = 17 staples
Percent of change = 
Percent of change = 
Percent of change = 0.447*100
Percent of change = 44.7%
Hence,
The percent of change is 44.7%