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3 years ago

How can we classify the following shape ? Pleasee answer correctly !!!!!!!!!! Will

Mathematics

2 answers:

zvonat [6]3 years ago

6 0

Answer:

Step-by-step explanation:

Komok [63]3 years ago

5 0

Answer:

Step-by-step explanation:

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If a book cost $5 and the sales tax rate is 6.5%, how much would the book cost?

marin [14]

Answer:

$5.33

Step-by-step explanation:

6 0

3 years ago

Who can finish this for me

Paladinen [302]

Answer:

Step-by-step explanation:

$(5 - 5 {x}^{4} - {x}^{3} ) - (6 {x}^{3} - 4 {x}^{4} - 3)$

Remove unnecessary parentheses

$5 - 5 {x}^{4} - {x}^{3} - (6 {x}^{3} - 4 {x}^{4} - 3)$

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

$5 - 5 {x}^{4} - {x}^{3} - 6 {x}^{3} + 4 {x}^{4} + 3$

Collect like terms

$5 + 3 - 5 {x}^{4} + 4 {x}^{4} - {x}^{3} - 6 {x}^{3}$

$5 + 3 - {x}^{4} - 7 {x}^{3}$

Add the numbers

$8 - {x}^{4} - 7 {x}^{3}$

Use the commutative property to reorder the terms

$- {x}^{4} - 7 {x}^{3} + 8$

Hope this helps...

Best regards!!

8 0

4 years ago

What is the slope of a line parallel to the line -3x + 5y = -10?

mel-nik [20]

Y=0.6x+5 is the slope of a line parallel to the line -3x+5y=-10

4 0

4 years ago

In Major League Baseball, the American League (AL) allows a designated hitter (DH) to bat in place of the pitcher, but in the Na

hammer [34]

Answer:

Step-by-step explanation:

From the given information:

Let:

$\mu_1$ represent the population mean no. for DH group.

$\mu_2$ represent the population mean no. for no DH group

$n_1$ represent the sample sizes of DH

$n_2$ represent the sample sizes of no DH

Sample size: $n_1 = n_2 = 20$

For both groups, the population standard deviation of runs scored = 2.54

i.e

$\sigma^2_1 = \sigma_2^2 = 2.54$

The null & alternative hypothesis;

$H_o : \mu_1 \le \mu_2 \\ \\ H_a: \mu_1 > \mu_2$

Level of significance:

The test statistics is:

$z = \dfrac{\bar x_1 - \bar x_2}{\sqrt{\dfrac{\sigma^2_1}{n_1} + \dfrac{\sigma_2^2}{n_2} }}$

where;

$\bar x_1$ = sample mean for DH group

$\implies \dfrac{1}{n_1} \sum \limit ^{n_1}_{i=1} x_1 \\ \\ = \dfrac{1}{20}(0+6+8+2+2+4+7+7+6+5+1+1+5+4+4+5+7+11+10+0) \\ \\ = \dfrac{92}{20}$

= 4.6

$\bar x_2$ = sample mean for no DH group

$\implies \dfrac{1}{n_2} \sum \limit ^{n_1}_{i=1} x_1 \\ \\ = \dfrac{1}{20}(3+6+2+4+0+5+7+6+1+8+12+4+6+3+4+0+5+2+1+4) \\ \\ = \dfrac{83}{20}$

= 4.15

Now:

$z = \dfrac{4.60- 4.15}{\sqrt{\dfrac{2.54^2}{20} + \dfrac{2.54^2}{20} }} \\ \\ = \dfrac{0.45}{\sqrt{0.32258 +0.32258 }} \\ \\ = \dfrac{0.45}{0.803219} \\ \\$

= 0.5602

Since the test is one-tailed by looking at that $H_a:$

The P-value = $P(Z > z)$

$\implies 1 - P(Z \le z) \\ \\ = 1 - P(Z \le 0.5602)$

Using Excel Function " =normdist(z)"; we have":

$= 1- 0.7123$

P-value = 0.2877

Decision rule: To reject $H_o$ , if $p-value < \alpha \ at \ 0.10$

Conclusion: SInce P = 0.2877 which is $> \ \alpha \ at \ 0.10.$

We fail to reject the $H_o$ and conclude that there is insufficient evidence to support the given claim that: $\text{more runs are scored in games for which DH is used.}$

8 0

3 years ago

I’m a football game the home team scored 2 times as many points as the visiting team, if the game ended with a total of 21 point

Vlad1618 [11]

The visiting team scored ten points

3 0

2 years ago