How do you solve -3log5x=-6?
1 answer:
-3log5x = -6 would equal x = 25.
First, use the Power Rule: (log b x
= c log b x). Your problem should look like -log5 x³ = -6.
Second, multiply both sides by -1. Your problem should look like log5 x³ = 6. We removed the negative signs.
Third, use the Definition of Common Logarithms. ( b
= x if and only if logb(x) = a). Your problem should look like x³ = 5
.
Fourth, simplify 5 to 15625. Your problem should look like x³ = 15625.
Fifth, take the cube root of both sides. Your problem should look like x = 3√15625.
Sixth, calculate your problem to get x = 25 which is the answer.
First, use the Power Rule: (log b x
Second, multiply both sides by -1. Your problem should look like log5 x³ = 6. We removed the negative signs.
Third, use the Definition of Common Logarithms. ( b
Fourth, simplify 5
Fifth, take the cube root of both sides. Your problem should look like x = 3√15625.
Sixth, calculate your problem to get x = 25 which is the answer.
You might be interested in
If and
are inverse proportional to one another, then for some constant volume
we have
It takes 45 min to empty a tank containing at 300 gal/min, so the tank contains
of liquid.
If it's emptied at 500 gal/min, it would take