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snow_tiger [21]
3 years ago
8

On a factory floor, 30 out of every 140 toy robots is defective. What percent of you robots are defective? Round to the nearest

hundredth.
Mathematics
2 answers:
Gekata [30.6K]3 years ago
7 0
30 out of 140
that means the equation is 30/140
that equals .2142 . . .
that moves over the 21%
geniusboy [140]3 years ago
5 0

Answer: 21.43 %


Step-by-step explanation:

Given: On a factory floor, 30 out of every 140 toy robots is defective.

Thus, the total number of robots = 140

The number of defective robots = 30

Now the percent of robots which are defective= \frac{\text{defective robots}}{\text{total robots}}\times100

=\frac{30}{140}\times100

=21.42857\%\approx21.43\%

Hence, the percent  of robots which are defective = 21.43 %

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miv72 [106K]

It will be b : KikaKika 700:

Step-by-step explanation:

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2 years ago
1/3(x-1/3)-1/2(2/3x-1/2)
kenny6666 [7]

For this case we must simplify the following expression:

\frac {1} {3} (x- \frac {1} {3}) - \frac {1} {2} (\frac {2} {3} x- \frac {1} {2})

So, if we apply distributive property to the terms within parentheses we have:

\frac {1} {3} x- \frac {1} {9} - \frac {2} {6} x + \frac {1} {4} =\\\frac {1} {3} x- \frac {1} {9} - \frac {1} {3} x + \frac {1} {4} =

We simplify taking into account that:

  • Equal signs are added and the same sign is placed.
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- \frac {1} {9} + \frac {1} {4} =\\- \frac {4} {36} + \frac {9} {36} =\\\frac {-4 + 9} {36} =\\\frac {5} {36}

Answer:

\frac {5} {36}

4 0
3 years ago
Use the order of operations to simplify the expression
xxMikexx [17]

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Read 2 more answers
What is a35 for the arithmetic sequence presented in the table below?
Kryger [21]

Answer: choice B) a35 = -118

=====================================================

Explanation:

When n = 5, an = 32 as shown in the first column of the table. This means the fifth term is 32. Plug in those values to get

an = a1+d(n-1)

32 = a1+d(5-1)

32 = a1+4d

Solve for a1 by subtracting 4d from both sides

a1 = 32-4d

We'll plug this in later

Turn to the second column of the table. We have n = 10 and an = 7. Plug those values into the formula

an = a1+d(n-1)

7 = a1 + d(10-1)

7 = a1+9d

Now substitute in the equation in which we solved for a1

7 = a1+9d

7 = 32-4d+9d ... replace a1 with 32-4d

7 = 32+5d

5d = 7-32

5d = -25

d = -25/5

d = -5

This tells us that we subtract 5 from each term to get the next term.

Use this d value to find a1

a1 = 32-4d

a1 = 32-4*(-5)

a1 = 32+20

a1 = 52

The first term is 52

--------------

The nth term formula is therefore

an = 52 + (-5)(n-1)

which simplifies to

an = -5n + 57

To check this result, plug in n = 5 to find that a5 = 32. Similarly, you'll find that a10 = 7 after plugging in n = 10. I'll let you do these checks.

--------------

Replace n with 35 to find the 35th term

an = -5n + 57

a35 = -5(35) + 57

a35 = -175 + 57

a35 = -118

7 0
3 years ago
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Tema [17]

Answer:

x = 1 + sqrt(89) or x = 1 - sqrt(89)

Step-by-step explanation:

Solve for x:

(x - 9) (x + 7) = 25

Expand out terms of the left hand side:

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Add 63 to both sides:

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Add 1 to both sides:

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Take the square root of both sides:

x - 1 = sqrt(89) or x - 1 = -sqrt(89)

Add 1 to both sides:

x = 1 + sqrt(89) or x - 1 = -sqrt(89)

Add 1 to both sides:

Answer: x = 1 + sqrt(89) or x = 1 - sqrt(89)

7 0
4 years ago
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