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3 years ago

What’s the solution? How do you do this?

Mathematics

1 answer:

RoseWind [281]3 years ago

4 0

Answer:

Not congruent.

Step-by-step explanation:

We can solve this by checking if all of the angles inside the triangle are congruent. We can first check the angles inside ΔSPY.

180°-64°-28°= 88°.

For the triangles to be congruent, all of the matching angles must be the same. This means that for example, ∠A and ∠S have to be the same.

However, we derived that ∠S=88° and ∠A= 78°. This means that the triangles are not congruent.

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your grades on tests 1 2 and 4 are 82 76 and 90. unfortunately you cut the third test and received a 0. If you have one test lef

Dmitrij [34]

Answer: No, he can't pass the course.

Explanation:

Since we have given that

Marks on tests 1, 2, and 4 are given by

82, 76, 90 respectively.

Unfortunately, he cut the third test and receive a 0.

According to question, we have given that passing grade for the course is 70, and his one test left to take ,

Let the marks obtained in fifth test be x

So,

$\frac{82+76+90+0+x}{5}=70\\\\248+x=5\times 70=350\\\\x=350-248\\\\x=102$

And it is not possible to get 102 over 100.

so, he can't still pass the course.

Hence, No, he can't pass the course.

8 0

4 years ago

Show that sin (30°) = 1/2

Natali [406]

Answer:

Geometric proof in explanation.

Step-by-step explanation:

Draw an equilateral triangle.

A equilateral triangle has it's sides all congruent and all it's angles measures 60 degrees.

We are going to draw a line segment to cut the equilateral triangles into two congruent right triangles. I will do this in the attachment with p being positive.

You can see we will get 30-60-90 triangles.

We don't need to find the adjacent measurement to the angle whose measurement is 30 degrees since sine is opposite over hypotenuse.

$\sin(30^\circ)=\frac{\frac{p}{2}}{p}=\frac{p}{2} \cdot \frac{1}{p}=\frac{1}{2}$

$\sin(30^\circ)=\frac{1}{2}$

7 0

3 years ago

6,651,297,000 in verbal form

sashaice [31]

Six billion, six hundred fifty one million, two hundred ninety seven thousand.

7 0

3 years ago

What are the factors of 6tu

creativ13 [48]

Depending on the value of 't' and 'u', the numerical value of that expression
could have almost anything for factors.

For example, if 't' happens to be 3 and 'u' happens to be 10, then 6tu = 180,
and the factors of 6tu are

1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, and 180.

But that would only be temporary ... only as long as t=3 and u=10.

The only factors you can always count on, that don't depend on the values
of 't' and 'u', are

1, 6, t, u, 6t, 6u, tu, and 6tu .

6 0

4 years ago

Which expression would be easier to simplify if you used the associative property to change the grouping?

vlabodo [156]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers