Volume of a cylinder= π r^2 h
.4= radius
π• 4^2 • 3= 150. 79
Answer:
The 88% confidence level for the average weight gain if between -1.30 lbs and 4.58 lbs.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 23 - 1 = 22
88% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 22 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.6176
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 1.64 - 2.94 = -1.30 lbs
The upper end of the interval is the sample mean added to M. So it is 1.64 + 2.94 = 4.58 lbs
The 88% confidence level for the average weight gain if between -1.30 lbs and 4.58 lbs.
The formula of a volume of a sphere:

R - radius
We have the volume = 288 in³. Substitute:
![\dfrac{4}{3}\pi R^3=288\qquad\text{multiply both sides by 3}\\\\4\pi R^3=864\qquad\text{divide both sides by}\ 4\pi\\\\R^3=\dfrac{216}{\pi}\to R=\sqrt[3]{\dfrac{216}{\pi}}\\\\R=\dfrac{\sqrt[3]{216}}{\sqrt[3]{\pi}}\\\\R=\dfrac{6}{\sqrt[3]{\pi}}\ in](https://tex.z-dn.net/?f=%5Cdfrac%7B4%7D%7B3%7D%5Cpi%20R%5E3%3D288%5Cqquad%5Ctext%7Bmultiply%20both%20sides%20by%203%7D%5C%5C%5C%5C4%5Cpi%20R%5E3%3D864%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%7D%5C%204%5Cpi%5C%5C%5C%5CR%5E3%3D%5Cdfrac%7B216%7D%7B%5Cpi%7D%5Cto%20R%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B216%7D%7B%5Cpi%7D%7D%5C%5C%5C%5CR%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B216%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%7D%7D%5C%5C%5C%5CR%3D%5Cdfrac%7B6%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%7D%7D%5C%20in)
The formula of a surface area of a sphere:

Substitute:
![S.A.=4\pi\left(\dfrac{6}{\sqrt[3]{\pi}}\right)^2=4\pi\cdot\dfrac{6^2}{\sqrt[3]{\pi^2}}=\dfrac{4\pi\cdot36}{\sqrt[3]{\pi^2}}=\dfrac{144\pi}{\sqrt[3]{\pi^2}}\\\\S.A.=\dfrac{144\pi}{\sqrt[3]{\pi^2}}\cdot\dfrac{\sqrt[3]{\pi}}{\sqrt[3]{\pi}}=\dfrac{144\pi\sqrt[3]{\pi}}{\sqrt[3]{\pi^3}}=\dfrac{144\pi\sqrt[3]{\pi}}{\pi}=\boxed{144\sqrt[3]{\pi}\ in^2}](https://tex.z-dn.net/?f=S.A.%3D4%5Cpi%5Cleft%28%5Cdfrac%7B6%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%7D%7D%5Cright%29%5E2%3D4%5Cpi%5Ccdot%5Cdfrac%7B6%5E2%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%5E2%7D%7D%3D%5Cdfrac%7B4%5Cpi%5Ccdot36%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%5E2%7D%7D%3D%5Cdfrac%7B144%5Cpi%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%5E2%7D%7D%5C%5C%5C%5CS.A.%3D%5Cdfrac%7B144%5Cpi%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%5E2%7D%7D%5Ccdot%5Cdfrac%7B%5Csqrt%5B3%5D%7B%5Cpi%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%7D%7D%3D%5Cdfrac%7B144%5Cpi%5Csqrt%5B3%5D%7B%5Cpi%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%5E3%7D%7D%3D%5Cdfrac%7B144%5Cpi%5Csqrt%5B3%5D%7B%5Cpi%7D%7D%7B%5Cpi%7D%3D%5Cboxed%7B144%5Csqrt%5B3%5D%7B%5Cpi%7D%5C%20in%5E2%7D)
13*18
x*y =234
x+y=31
we know the 2 # have to be double digits and both between 10-20
find 2 values that * to a number that ends in 4. Those are the ones value
1*4 11 and 14
2*2 12 and 12
3*8 13 and 18
only 13 and 18 add up to 31 and multiply to 234
Answer:
609 males
Step-by-step explanation:
A city council organized a marathon race to promote good health.
Let the number of
Females = x
Males = y
There were 3 times as many female participants as male participants in the marathon.
3x = y
If the total number of participants was 812,
x + y = 812..... Equation 1
We substitute 3x for y in Equation 1
x + 3x = 812
4x = 812
x= 812/4
x = 203 females
3x = y
Solving for y
3(203) = 609 males
The number of males participants = 609