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horrorfan [7]
3 years ago
11

X + 5 ≤ 13 what's the answer for this question?​

Mathematics
1 answer:
wariber [46]3 years ago
6 0

Answer:

Inequality Form: x ≤ 8

Interval Notation: (-∞,8]

Step-by-step explanation:

x + 5 ≤ 13

Subtract 5 on both sides...

13 - 5 = 8

You're left with x ≤ 8

Inequality Form: x ≤ 8

Interval Notation: (-∞,8]

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The answer should be 52
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A hiker carried 1 gallon of water on a hike. She drank 1/2 of the water when she stopped to rest and gave an equal amount of the
m_a_m_a [10]

Answer:

The answer to your question is 1/8

Step-by-step explanation:

Data

Total volume = 1 gallon

Water drank by the hiker = 1/2

Water drank by each of his friends = ?

Process

1.- Calculate the water that he gave to his friends

Water gave to his friends = 1 - 1/2

                                          = 1/2

2.- Calculate the amount of water each friend received.

            1/2 ÷ 4 = 1/8

3.- Conclusion

Each of the friends received 1/8 of the gallon.              

6 0
3 years ago
Use lagrange multipliers to find the shortest distance, d, from the point (4, 0, −5 to the plane x y z = 1
Varvara68 [4.7K]
I assume there are some plus signs that aren't rendering for some reason, so that the plane should be x+y+z=1.

You're minimizing d(x,y,z)=\sqrt{(x-4)^2+y^2+(z+5)^2} subject to the constraint f(x,y,z)=x+y+z=1. Note that d(x,y,z) and d(x,y,z)^2 attain their extrema at the same values of x,y,z, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.

The Lagrangian is

L(x,y,z,\lambda)=(x-4)^2+y^2+(z+5)^2+\lambda(x+y+z-1)

Take your partial derivatives and set them equal to 0:

\begin{cases}\dfrac{\partial L}{\partial x}=2(x-4)+\lambda=0\\\\\dfrac{\partial L}{\partial y}=2y+\lambda=0\\\\\dfrac{\partial L}{\partial z}=2(z+5)+\lambda=0\\\\\dfrac{\partial L}{\partial\lambda}=x+y+z-1=0\end{cases}\implies\begin{cases}2x+\lambda=8\\2y+\lambda=0\\2z+\lambda=-10\\x+y+z=1\end{cases}

Adding the first three equations together yields

2x+2y+2z+3\lambda=2(x+y+z)+3\lambda=2+3\lambda=-2\implies \lambda=-\dfrac43

and plugging this into the first three equations, you find a critical point at (x,y,z)=\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right).

The squared distance is then d\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right)^2=\dfrac43, which means the shortest distance must be \sqrt{\dfrac43}=\dfrac2{\sqrt3}.
7 0
3 years ago
James is kayaking. He can row 3 mph in still water. If he can travel 6 miles downstream in the same amount of time that he can t
nekit [7.7K]

Answer: the speed of the current is 0.6 mph

Step-by-step explanation:

Let x represent the speed of the current.

James is kayaking. He can row 3 mph in still water. If he can travel 6 miles downstream. Assuming he went with the current, it means that his total speed while travelling downstream is (3 + x)

Time = distance/speed

Time taken to travel downstream is

6/(3 + x)

In the same amount of time, he can travel 4 miles upstream. Assuming he went against the current, it means that his total speed while travelling downstream is (3 - x). Time taken to travel upstream is

4/(3 - x)

Since the time is the same, then

6/(3 + x) = 4/(3 - x)

Cross multiplying, it becomes

6(3 - x) = 4(3 + x)

18 - 6x = 12 + 4x

4x + 6x = 18 - 12

10x = 6

x = 6/10

x = 0.6 mph

4 0
3 years ago
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