In 2016, a billionaire's net worth was approximately $3.6 x 109. That same year, it

Mathematics

1 answer:

Alekssandra [29.7K]4 years ago

3 0

Answer:

all you do is multiply 3.6 and 109 to see if its 45,000 per year

Step-by-step explanation:

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Easy question

Leviafan [203]

$\dfrac{\mathrm dy}{\mathrm dt}=ky\iff\dfrac{\mathrm dy}y=k\,\mathrm dt$

Integrating both sides, we get

$\ln|y|=kt+C$
$\implies y=e^{kt+C}=e^{kt}e^C=Ce^{kt}$

When $t=0$ , we have $y=10000$ , so that

$10000=Ce^{0k}\implies C=10000$

When $t=4$ , we have $y=8000$ , which means

$8000=10000e^{4k}\implies k=\dfrac14\ln\dfrac{8000}{10000}\approx-0.0558$

5 0

3 years ago

How to find the limit of that question

jeka94

Factor the numerator using difference of cubes:
$a^3 - b^3 = (a-b)(a^2 +ab+b^2)$
a = x
b = 2

$\frac{x^3 - 8}{x-2} = \frac{(x-2)(x^2 +2x+4)}{x-2} = x^2 +2x+4$

Now you can evaluate limit as x=2.
$\lim_{x \to 2} (x^2 +2x+4) = 2^2 +2(2)+4 = 12$