We have to solve this equation:

Third degree polynomials like this one are not easily solved, but this one has a root at x = 0. The let us factorize this polynomial as x times a second degree polynomial:

Now we can find the roots of the quadratic polynomial as:
![\begin{gathered} x=\frac{-(-6)\pm\sqrt[]{(-6)^2-4\cdot1\cdot6}}{2\cdot1} \\ x=\frac{6\pm\sqrt[]{36-24}}{2} \\ x=\frac{6\pm\sqrt[]{12}}{2} \\ x=\frac{6\pm\sqrt[]{4\cdot3}}{2} \\ x=\frac{6\pm2\sqrt[]{3}}{2} \\ x=3\pm\sqrt[]{3} \\ x_1=3-\sqrt[]{3} \\ x_2=3+\sqrt[]{3} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B-%28-6%29%5Cpm%5Csqrt%5B%5D%7B%28-6%29%5E2-4%5Ccdot1%5Ccdot6%7D%7D%7B2%5Ccdot1%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm%5Csqrt%5B%5D%7B36-24%7D%7D%7B2%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm%5Csqrt%5B%5D%7B12%7D%7D%7B2%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm%5Csqrt%5B%5D%7B4%5Ccdot3%7D%7D%7B2%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm2%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%20%5C%5C%20x%3D3%5Cpm%5Csqrt%5B%5D%7B3%7D%20%5C%5C%20x_1%3D3-%5Csqrt%5B%5D%7B3%7D%20%5C%5C%20x_2%3D3%2B%5Csqrt%5B%5D%7B3%7D%20%5Cend%7Bgathered%7D)
Then, the solutions to the equation are:
x = 0
x = 3 - √3
x = 3 + √3
Answer:
6 blocks each measuring One-third times 1 times 1
Step-by-step explanation:
Answer:
Place the paranthases around 5-2
Step-by-step explanation:
Answer:
The correct option is C) r=-0.80
Step-by-step explanation:
Consider the provided information.
Properties of r in a scatter plot:
The value of r is between -1 and +1.
If the value of r is positive then it associated with positive relationship if the value of r is negative it associated with negative value.
The greater value of r would be closely around a straight line(Regardless of sign).
Now consider the provided relation.
The use of regression line is to minimize the distance between projections and real values.
Correlation is inversely proportional to difference between predicted values and actual values.
So for good fit we just need to look for the highest value of r regardless of the sign.
From the provided options the highest value of r=-0.80
Thus, the correct option is C) r=-0.80
Solution:
Consider the following diagram
extremes and means are multiplied in the diagram. Then we have that:

and this number is represented on the real line as follows: