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4 years ago

What number is half-way between 14 and 42?

Mathematics

2 answers:

qaws [65]4 years ago

6 0

I believe the answer is 28.

IgorC [24]4 years ago

3 0

Your answer will be 38 because when we add 14 2 times then we get 28 and when we subtract 14 we get 14 and when we add 14 we get 42. M

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Math question please help

denpristay [2]

Answer:

a. 4

b. 132

Step-by-step explanation:

Plugg in the equation in desmos graphing calculator and the find the vertex to find the answer.

(Are you doing this in pearson?)

6 0

3 years ago

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The follow

kipiarov [429]

Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

$H_0: \mu = 13252$

At the alternative hypothesis, we test if the mean cost has increased, that is:

$H_1: \mu > 13252$

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

13252 is tested at the null hypothesis:

This means that $\mu = 13252$

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that $n = 20, X = 15560, s = 3500$

Value of the test statistic:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}$

$t = 2.95$

P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

7 0

3 years ago

Aaron has 50cent. he buys a pencil for 40cent how much change does he get

lana [24]

Answer:

10¢

Step-by-step explanation:

Step 1: Subtract 40 from 50

$50 - 40 = 10$