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notsponge [240]
3 years ago
8

Is this is right, please help

Mathematics
2 answers:
frozen [14]3 years ago
7 0
7:54...10:55 - 33 minutes is 10:22.  Then subtract 2 hours, brings you to 8:22.  Then subtract 28 minutes, and is 7:54
Bond [772]3 years ago
4 0
I think so sorry I’m not good with this hehe
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Solve the equation and explain each step using apropriate Properties<br> -4(3x+6)+6=-30
Lina20 [59]

Answer:

The answer is x=1

Step-by-step explanation:

-4(3x+6)+6=-30

-12x-24+6=-30

-12x-18=-30

-12x-18+18=-30+18

-12x=-12

-12x/-12=-12/-12

x=1

6 0
2 years ago
(x +y)^5<br> Complete the polynomial operation
Vesna [10]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the polynomial

\left(x+y\right)^5

\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i

a=x,\:\:b=y

=\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i

so expanding summation

=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5

solving

\frac{5!}{0!\left(5-0\right)!}x^5y^0

=1\cdot \frac{5!}{0!\left(5-0\right)!}x^5

=1\cdot \:1\cdot \:x^5

=x^5

also solving

=\frac{5!}{1!\left(5-1\right)!}x^4y

=\frac{5}{1!}x^4y

=\frac{5}{1!}x^4y

=\frac{5x^4y}{1}

=\frac{5x^4y}{1}

=5x^4y

similarly, the result of the remaining terms can be solved such as

\frac{5!}{2!\left(5-2\right)!}x^3y^2=10x^3y^2

\frac{5!}{3!\left(5-3\right)!}x^2y^3=10x^2y^3

\frac{5!}{4!\left(5-4\right)!}x^1y^4=5xy^4

\frac{5!}{5!\left(5-5\right)!}x^0y^5=y^5

so substituting all the solved results in the expression

=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5

=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5

Therefore,

\left(x\:+y\right)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5

6 0
2 years ago
Sam has $440 in $20, $10, and $5 dollar bills. The number of twenties, tens and fives are consecutive integers in this order. Ho
Ludmilka [50]

Answer: There are 12 bills for $20, 13 bills for $10 and 14 bills for $5.

Step-by-step explanation:

Let the number of twenties be x

Let the number of tens be x+1

Let the number of fives be x+2

Amount from twenties will be given as

20\times x=20x

Amount from tens will be given as

10\times (x+1)=10x+10

Amount from fives will be given as

5\times (x+2)=5x+10

According to question,

20x+10x+10+5x+10=440\\\\35x+20=440\\\\35x=440-20\\\\35x=420\\\\x=\frac{420}{35}\\\\x=12

So, there are 12 bills for $20, 13 bills for $10 and 14 bills for $5.

6 0
3 years ago
Match each pair of equivalent fractions.
coldgirl [10]

1 would be D

2 would be C

3 would be A

4 would be B

3 0
3 years ago
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A chord PQ of length 13cm is drawn in a circle with center C and a radius of 10.2cm.
Reika [66]
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3 0
2 years ago
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