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notsponge [240]

3 years ago

8

Is this is right, please help

2 answers:

frozen [14]3 years ago

7 0

7:54...10:55 - 33 minutes is 10:22. Then subtract 2 hours, brings you to 8:22. Then subtract 28 minutes, and is 7:54

Bond [772]3 years ago

4 0

I think so sorry I’m not good with this hehe

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Solve the equation and explain each step using apropriate Properties<br> -4(3x+6)+6=-30

Lina20 [59]

Answer:

The answer is x=1

Step-by-step explanation:

-4(3x+6)+6=-30

-12x-24+6=-30

-12x-18=-30

-12x-18+18=-30+18

-12x=-12

-12x/-12=-12/-12

x=1

6 0

2 years ago

(x +y)^5<br> Complete the polynomial operation

Vesna [10]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the polynomial

$\left(x+y\right)^5$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=x,\:\:b=y$

$=\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i$

so expanding summation

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$

solving

$\frac{5!}{0!\left(5-0\right)!}x^5y^0$

$=1\cdot \frac{5!}{0!\left(5-0\right)!}x^5$

$=1\cdot \:1\cdot \:x^5$

$=x^5$

also solving

$=\frac{5!}{1!\left(5-1\right)!}x^4y$

$=\frac{5}{1!}x^4y$

$=\frac{5}{1!}x^4y$

$=\frac{5x^4y}{1}$

$=\frac{5x^4y}{1}$

$=5x^4y$

similarly, the result of the remaining terms can be solved such as

$\frac{5!}{2!\left(5-2\right)!}x^3y^2=10x^3y^2$

$\frac{5!}{3!\left(5-3\right)!}x^2y^3=10x^2y^3$

$\frac{5!}{4!\left(5-4\right)!}x^1y^4=5xy^4$

$\frac{5!}{5!\left(5-5\right)!}x^0y^5=y^5$

so substituting all the solved results in the expression

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$

$=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

Therefore,

$\left(x\:+y\right)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

6 0

2 years ago

Sam has $440 in $20, $10, and $5 dollar bills. The number of twenties, tens and fives are consecutive integers in this order. Ho

Ludmilka [50]

Answer: There are 12 bills for $20, 13 bills for $10 and 14 bills for $5.

Step-by-step explanation:

Let the number of twenties be x

Let the number of tens be x+1

Let the number of fives be x+2

Amount from twenties will be given as

$20\times x=20x$

Amount from tens will be given as

$10\times (x+1)=10x+10$

Amount from fives will be given as

$5\times (x+2)=5x+10$

According to question,

$20x+10x+10+5x+10=440\\\\35x+20=440\\\\35x=440-20\\\\35x=420\\\\x=\frac{420}{35}\\\\x=12$

So, there are 12 bills for $20, 13 bills for $10 and 14 bills for $5.

6 0

3 years ago

Match each pair of equivalent fractions.

coldgirl [10]

1 would be D

2 would be C

3 would be A

4 would be B

3 0

3 years ago

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Reika [66]

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2 years ago