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Bess [88]
3 years ago
12

What is the area of this triangle? please help me.

Mathematics
2 answers:
motikmotik3 years ago
8 0

Answer:

6 units²

Step-by-step explanation:

The area (A) of a triangle is calculated using the formula

A = \frac{1}{2} bh ( b is the base and h the height )

here b = DE = 3 units and

h is the distance from the vertex F to DE = 4 units, hence

A = \frac{1}{2} × 3 × 4 = 6 units²

olchik [2.2K]3 years ago
5 0

Answer:

6

Step-by-step explanation:

Area of a triangle: bh/2

4*3/2=6

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Answer:

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3 years ago
Graphing Exponential Function in Exercise ,sketch the graph of the function.See example 3 and 4.
boyakko [2]

Answer:

graphic attached

Step-by-step explanation:

Hi

when t = 0 then s (t) = 1/4

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8 0
3 years ago
Manuel and Sonja are shopping for school supplies. Manuel is buying 5 notebooks and 3 pens at a cost of $21. Sonja is buying 6 n
brilliants [131]

Answer: 6x+5y=28

Step-by-step explanation:

Looking at the first equation, we can tell that x stands for notebooks and y stand for pens. Since this talks about the total cost with the amount of products they bought, we can automatically eliminate the subtracting answer choices.

Now, we know that 6x+57=28 is the correct answer because Sonja bought 6 notebooks and 5 pens. This becomes 6x+5y.

3 0
3 years ago
For which values of P and Q does the following equation have infinitely many solutions? Px-37=Qx-37
Lyrx [107]

Answer:

The equation has infinitely many solutions for any value of P and Q such that P=Q.

Step-by-step explanation:

Px - 37 = Qx - 37

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4 0
3 years ago
given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta
lapo4ka [179]

Answer:

\cos{\theta} = \frac{\sqrt{15}}{4}

Step-by-step explanation:

For any angle \theta, we have that:

(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1

Quadrant:

0 \leq \theta \leq \frac{\pi}{2} means that \theta is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1

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(\cos{\theta})^{2} = 1 - \frac{1}{16}

(\cos{\theta})^{2} = \frac{16-1}{16}

(\cos{\theta})^{2} = \frac{15}{16}

\cos{\theta} = \pm \sqrt{\frac{15}{16}}

Since the angle is in the first quadrant, the cosine is positive.

\cos{\theta} = \frac{\sqrt{15}}{4}

3 0
3 years ago
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