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madreJ [45]
3 years ago
8

Whats 20 +15(72-13)-67+6

Mathematics
2 answers:
AlexFokin [52]3 years ago
8 0
Order of operations.

Parentheses
Exponents
Multiplication
Division
Addition
Subtraction

We must do parenthesis first.

72 - 13 = 59

We have now
20 + 15(59) - 67 + 6
20 + 885 - 67 + 6
905 - 67 + 6
905 - 61
844

Hope this helped! If you have any questions then leave a comment.
Delicious77 [7]3 years ago
8 0

Good morning

20+15(72-13)-67+6

= 20+15(59)-67+6

= 20+885-67+6

= 905-67+6

= 838+6

= 844


I hope that's help !


Happy Sunday :)


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Which expressions are equivalent to 2 ln a 2 ln b - ln a? Check all that apply. Ln ab2 - ln a ln a 2 ln b ln a2 ln b2 - ln a 2 l
marysya [2.9K]

Equivalent expressions are expressions with same simplified form. Equivalent expressions for the given expression are;

  • Expression 2:  \ln(a) + 2\ln(b) = \ln(a) + \ln(b^2)  = \ln(ab^2)
  • Expression 3:  \ln(a^2) + \ln(b^2) - \ln(a) = \ln(a^2b^2/a) = \ln(ab^2)
  • Expression 5:  \ln(ab^2)

<h3>What are equivalent expressions?</h3>

Those expressions who might look different but their simplified forms are same expressions are called equivalent expressions.

To derive equivalent expressions of some expression, we can either make it look more complex or simple. Usually, we simplify it.

<h3>What is logarithm and some of its useful properties?</h3>

When you raise a number with an exponent, there comes a result.

Lets say you get

a^b = c

Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows

b = log_a(c)

Some properties of logarithm are:

log_a(b) = log_a(c) \implies b = c\\\\\log_a(b) + log_a(c) = log_a(b \times c)\\\\log_a(b) - log_a(c) = log_a(\frac{b}{c})\\\\log_a(b^c) = c \times log_a(b)\\\\log_b(b) = 1\\\\ log_a(b) + log_b(c) = log_a(c)

Log with base e = 2.71828.... is written as \ln(x) simply.

The expression given is 2\ln(a) + 2\ln(b) - \ln(a)

We get its simplified form as

2\ln(a) + 2\ln(b) - \ln(a) = \ln(a) + \ln(b^2) = \ln(ab^2)

Simplifying given expressions:

  • Expression 1:  \ln(ab^2) - \ln(a) = \ln(ab^2/a)  = \ln(b^2)

This isn't same as simplified form of original

. Thus , this expression is not equivalent to the given expression.

  • Expression 2:  \ln(a) + 2\ln(b) = \ln(a) + \ln(b^2)  = \ln(ab^2)

This is same as simplified form of original expression. Thus , this expression is equivalent to the given expression.

  • Expression 3:  \ln(a^2) + \ln(b^2) - \ln(a) = \ln(a^2b^2/a) = \ln(ab^2)

This is same as simplified form of original expression. Thus , this expression is equivalent to the given expression.

  • Expression 4:  2\ln(ab) = \ln((ab)^2) = \ln(a^2b^2)

This isn't same as simplified form of original expression. Thus , this expression is not equivalent to the given expression.

  • Expression 5:  \ln(ab^2)

This is same as simplified form of original expression. Thus , this expression is equivalent to the given expression.

Thus, equivalent expressions for the given expression are;

  • Expression 2:  \ln(a) + 2\ln(b) = \ln(a) + \ln(b^2)  = \ln(ab^2)
  • Expression 3:  \ln(a^2) + \ln(b^2) - \ln(a) = \ln(a^2b^2/a) = \ln(ab^2)
  • Expression 5:  \ln(ab^2)

Learn more about equivalent expressions here:

brainly.com/question/10628562

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My first expression answer is y=5 -2x How do I plug it into x-y=1 ?? The Y
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Answer:

All you need to do is make sure the first expression is solved for y (which it is), and then substitute it into the second expression in place of any occurrences of y:

given the second expression:

x - y = 1

We'll replace y with it's value in the first expression:

x - (y) = 1

x - (5 - 2x) = 1

Now we can expand the resulting equation:

x - 5 + 2x = 1

So <em>neither</em> of the answers provided are correct.

You can then solve for x:

x - 5 + 2x = 1

x - 5 + 5 + 2x = 1 + 5

x + 2x = 6

3x = 6

3x/3 = 6/3

x = 2

After that, you can find y by plugging x into either of the two original equations:

y = 5 - 2x

y = 5 - 2(2)

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Answer:

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Step-by-step explanation:

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