Answer:
Step-by-step explanation:
In choices a and b, the bases are positive numbers greater than 1, and so these are growth functions. In c and d, the bases are between 0 and 1, and thus these are decay functions.
In the second problem we have 3ln(x + 1). Rewrite this as ln(x + 1)^3.
We also have 9ln(x - 4). Rewrite this as ln(x - 4)^9.
Because of the + sign connecting ln(x + 1)^3 and ln(x - 4)^9, these two logs combine to form
ln [ (x + 1)^3 ] * (x - 4)^9 (the log of a product).
Now we have:
ln [ (x + 1)^3 ] * (x - 4)^9 - 4ln(x + 7), or:
[ (x + 1)^3 ] * (x - 4)^9
ln ------------------------------------
(x + 7)^9
