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Lorico [155]
3 years ago
13

I need the answers for these please

Mathematics
1 answer:
Luda [366]3 years ago
8 0
11.p=-8, 17-8=9
12.y=11, 3*11=33+16=46
13.t=4, 4*4=16-14=2
14.x=9, -9x 9*8=82-9=72-9=62
15.z=4, 12*4=48-18=30
16.g=0, 4*0=0, 7+0=7
17.x=4, 9*4=36-24=-3
18.q=3, 18*3=48+2=50
19.c=2, 3*2=6-4.5=4.1
20.y=4, 9+4=13+4.8=17.4

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<em>Comment on the problem</em>

Since you are given the base and height, we presume you are intended to use the formula above. You are also given all three side lengths. If you use the appropriate formula with those, you find the area is about 15.6 square inches. (The height of this triangle is actually closer to 5.2 inches.)

The figure represents a geometry that cannot exist. With the given base and height, the side lengths should be 5, not 6.

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