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Mama L [17]
3 years ago
15

Please help, ty if you do :D

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0

Answer:

Your Answer is going to be C

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Please help with this!!
lozanna [386]

Answer:

#1.---60%   #2.---$12.60 per hour

Step-by-step explanation:

#1. Since It was originally $50 you have 50% already, so what I did was I multiplied 50 by 2. this got me 100 which is a simpler way to calculate by. 50 to 80 dollars is a $30 change, so multiply that by 2 and you get 60. 60 will be your percent of change. You can double check this by multiplying 50 by .60, the answer will be 30 and 50+30=80

#2 Since Tyler starts off with $12 per hour with a 5% increase you will need to multiply 12*.05 this will get you the answer of 0.6 you then need to add $12, since that was his original payment. 12+0.6=12.60, so his final payment would by $12.60 per hour

5 0
2 years ago
A circle has a radius of 3. An arc in this circle has a central angle of 20°. What is the length of the arc? Either enter an exa
Semenov [28]

Answer:

\frac{\pi  }{3}

2 * \pi * 3  * \frac{20}{360}

120\pi/360 = \frac{\pi  }{3}

Step-by-step explanation:

5 0
2 years ago
Find the domain of h(x)=x-3/x^3-36x
Dovator [93]

There is some ambiguity here which could be removed by using parentheses.  I'm going to assume that you actually meant:

               x-3

h(x) = ---------------

          (x^3-36x)

To determine the domain of this function, factor the denominator:

x^3 - 36x = x(x^2 - 36) = x(x-6)(x+6)

The given function h(x) is undefined when the denominator = 0, which happens at {-6, 0, 6}.

Thus, the domain is "the set of all real numbers not equal to -6, 0 or 6."

Symbolically, the domain is   (-infinity, -6) ∪ (-6, 0) ∪ (0, 6) ∪ (6, +infinity).

3 0
3 years ago
All zeros of polynomial function 3x^4 +14x^2 -5
Marizza181 [45]

Answer:

Correct answer:  x₁ = 1 / √3 = √3 / 3  or  x₂ = - 1 / √3 = - √3 / 3

Step-by-step explanation:

Given:

3 x⁴ + 14 x² - 5 = 0   biquadratic equation

this equation is solved by a shift  x² = t and get:

3 t² + 14 t - 5 = 0

t₁₂ = (-14 ± √14² - 4 · 3 · 5) / 2 · 3 = (-14 ± √196 + 60) / 6

t₁₂ = (-14 ± √256) / 6 = (-14 ± 16) / 6

t₁ = -5   or  t₂ = 1 / 3

the solution t₁ = -5 is not accepted because it cannot be x² = -5

we accepted  t₂ = 1 / 3

x² =  1 / 3  ⇒  

x₁ = 1 / √3 = √3 / 3  or  x₂ = - 1 / √3 = - √3 / 3

God is with you!!!

5 0
3 years ago
Fr/ee points 3 i quit brainly i cheat/ed enough this semester
ohaa [14]
Too


Thanks


Hahahah

16263636
6 0
3 years ago
Read 2 more answers
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