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maria [59]
4 years ago
5

the larger triangle is a dilation of the smaller triangle with a center of dilation at (2,-1). Whatbis the scale factor of the d

ilation? A) 1/3, B) 1/2, C) 2, D) 3​

Mathematics
1 answer:
leva [86]4 years ago
5 0
I think it’s 2. You can see this because if you count the squares in the smaller triangle it is 3 along. You would then need to double the amount of squares on all sides. This makes the larger triangle now 6 squares along. 6/3 is 2 making the scale factor 2. (This is only if I have read the question correctly and we are calculating small to big. If I have read it wrong and it is big to small it would be 1/2)
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Determine the value of a so that x1-3x3=-3 2x1+ax2-x3=-2 (i)unique solution(ii)no solution(iii)many solutions
Ad libitum [116K]

Answer:

(i)unique solution

Explanation:

We solve for x1 thus in the first equation:

x1-3x3=-3

x1-9=-3

x1=-3+9

x1= 6

We solve for a thus in the second equation:

2x1+ax2-x3=-2

2+a2-x3=-2

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3 years ago
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Answer:

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3 years ago
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3 years ago
Find the value of c that completes the square for x2−15x+c
meriva

Answer:

The value of <em>c</em> is \frac{225}{4}.

Step-by-step explanation:

The perfect square of the difference between two numbers is:

(x-y)^{2}=x^{2}-2xy+y^{2}

The expression provided is:

x^{2}-15x+c

The expression is a perfect square of the difference between two numbers.

One of the number is <em>x</em> and the other is √<em>c</em>.

Use the above relation to compute the value of <em>c</em> as follows:

x^{2}-15x+c=(x-\sqrt{c})^{2}\\\\x^{2}-15x+c=x^{2}-2\cdot x\cdot\sqrt{c}+c\\\\15x=2\cdot x\cdot\sqrt{c}\\\\15=2\cdot\sqrt{c}\\\\\sqrt{c}=\frac{15}{2}\\\\c=[\frac{15}{2}]^{2}\\\\c=\frac{225}{4}

Thus, the value of <em>c</em> is \frac{225}{4}.

5 0
3 years ago
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