3 years ago

Find the area simply your answer

Mathematics

1 answer:

Troyanec [42]3 years ago

5 0

8(2x+9)

= 16x+72

Hope it helped

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Find the sum of the first six terms of a geometric progression .

Dominik [7]

Question:

Find the sum of the first six terms of a geometric progression.

1,3,9,....

Answer:

$S_6 = 364$

Step-by-step explanation:

For a geometric progression, the sum of n terms is:

$S_n = \frac{a(r^n - 1)}{r - 1}$

In the given sequence:

$a = 1$

$r = 3/1 =3$

$n = 6$

So:

$S_n = \frac{a(r^n - 1)}{r - 1}$

$S_6 = \frac{1 * (3^6 - 1)}{3 - 1}$

$S_6 = \frac{3^6 - 1}{2}$

$S_6 = \frac{728}{2}$

$S_6 = 364$

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3 years ago

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It is B 99.99% sure

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3 years ago

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The product of a number and -2/3 is -9/10<br> (20 Points)<br> What is the number?

poizon [28]

Answer:

$\large\boxed{n=\dfrac{27}{20}}$

Step-by-step explanation:

$\text{Let}\ n\ \text{is a number.}\\\\\text{The product of a number and}\ -\dfrac{2}{3}\ \text{is}\ -\dfrac{9}{10}:\\\\-\dfrac{2}{3}\cdot n=-\dfrac{9}{10}\\\\-\dfrac{2n}{3}=-\dfrac{9}{10}\qquad\text{change the signs}\\\\\dfrac{2n}{3}=\dfrac{9}{10}\qquad\text{cross multiply}\\\\(2n)(10)=(3)(9)\\\\20n=27\qquad\text{divide both sides by 20}\\\\\dfrac{20n}{20}=\dfrac{27}{20}\\\\\boxed{n=\dfrac{27}{20}}$