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marusya05 [52]
3 years ago
10

The product of a number and -2/3 is -9/10 (20 Points) What is the number?

Mathematics
2 answers:
poizon [28]3 years ago
8 0

Answer:

\large\boxed{n=\dfrac{27}{20}}

Step-by-step explanation:

\text{Let}\ n\ \text{is a number.}\\\\\text{The product of a number and}\ -\dfrac{2}{3}\ \text{is}\ -\dfrac{9}{10}:\\\\-\dfrac{2}{3}\cdot n=-\dfrac{9}{10}\\\\-\dfrac{2n}{3}=-\dfrac{9}{10}\qquad\text{change the signs}\\\\\dfrac{2n}{3}=\dfrac{9}{10}\qquad\text{cross multiply}\\\\(2n)(10)=(3)(9)\\\\20n=27\qquad\text{divide both sides by 20}\\\\\dfrac{20n}{20}=\dfrac{27}{20}\\\\\boxed{n=\dfrac{27}{20}}

Lana71 [14]3 years ago
3 0

Answer:

1 7/20

Step-by-step explanation:

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Go step by step to reduce the radical. <br> The square root of 96
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Answer:

Step-by-step explanation:

We want to reduce the radical. In order to do that, we want to find the factors of 96 that are square numbers

The factors of 96 are:

1, 96, 2, 48, 3, 32, 4, 24, 6, 16...

16 is a square number, so we can rewrite

\sqrt{96} = \sqrt{16*6}  = \sqrt{16} * \sqrt{6}  = 4\sqrt{6}

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How can I make these a single fraction?
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3x+4y+z=-2<br> 2y+3z=-8<br> z=-3
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Answer:

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Can someone please help me find the value of x
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Step-by-step explanation:

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A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
3 years ago
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