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Sever21 [200]
3 years ago
12

A.

Mathematics
1 answer:
taurus [48]3 years ago
6 0

search for the formula for net income

Step-by-step explanation:

that would help u more.

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Jose is a botanist studying production of coconuts by two different groups of his
Colt1911 [192]

Answer: 132

Step-by-step explanation:

Since we are informed that Group 1 of trees produced 25 percent more coconuts than Group 2 did and that Group 1 produced 165 coconuts, the number of coconuts that Group 2 produce will be:

= [100 / (100 + 25)] × 165

= 100/125 × 165

= 0.8 × 165

= 132

Group 2 produced 132 coconuts.

5 0
3 years ago
2x + 6 = 2x - 2<br> ??????????
svp [43]

2x-6=2x+2

We move all terms to the left:

2x-6-(2x+2)=0

We get rid of parentheses

2x-2x-2-6=0

We add all the numbers together, and all the variables

-8!=0

There is no solution for this equation

6 0
2 years ago
Rachel is packing up some og her old stuff into a box.A box can hold eight pounds.but she only filled ot up two quarters full.ho
Fiesta28 [93]
Hi there!

Since the total weight the box can hold is 8 pounds, and she filled up 2/4:

8 * 2/4 = 4

There were 4 pounds in the box. 

Hope this helps!
8 0
3 years ago
The sum of 6 consecutive odd numbers is 204. What is the fourth number in this sequence?​
stiv31 [10]

Answer:

35

Step-by-step explanation:

1. Set up a equation.

2. X is the first, so the ones after x are x+2, x+4, x+6, x+8, and x+10.

3. That means that x+x+2+x+4+x+6+x+8+x+10=204.

4. Simplify. You would get that 6x+30=204.

5. Solve for x. 6x=174, so x=29.

6. Get the fourth number in the sequence. 29+6=35.

Answer: The fourth number in this sequence is 35.

3 0
2 years ago
Factorize it<br>evaluate it<br>factorise it<br>evaluate<br>factorize<br><br><br><br>​
VARVARA [1.3K]

Answer:

(x^2+y^2+xy)(x^2+y^2-xy)

Step-by-step explanation:

Rewrite the middle term.

x^4+2x^2y^2-x^2y^2+y^4

Rerrange terms.

x^4+2x^2y^2+y^4-x^2y^2

Factor first three terms by perfect square rule.

(x^2+y^2)^2-x^2y^2

Rewrite x^2y^2 as (xy)^2.

(x^2+y^2)^2-(xy)^2

Since both terms are perfect squares, factor using the difference of squares formula, a^2-b^2=(a+b)(a-b) where a=x^2+y^2 and b=xy.

(x^2+y^2+xy)(x^2+y^2-(xy))

Remove parentheses.

(x^2+y^2+xy)(x^2+y^2-xy)

3 0
1 year ago
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