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4 years ago

Help me plz I’m struggling with this

Mathematics

1 answer:

elena-s [515]4 years ago

3 0

Answer:

AC = 8√3 AC = 7.65

A = 43.17° AB = 16.8

B = 46.83° B = 27°

Step-by-step explanation:

FIRST TRIANGLE

by using pythagorus theorem:

Hypo² = Base² + height²

19² = 13² + AC²

AC² = 19² - 13²

AC² = 192

AC = √192

AC = 8√3

sinФ =base/hypo

sin A = 13/19

A = sin^-1 (13/19)

A = 43.17°

43.17°+ B + 90° =180 (sum of angles of triangle)

B = 180° - 133.17°

= 46.83°

<h3>SECOND TRIANGLE</h3>

TanФ = base/height

Tan 63° = 15 / AC

1.96 = 15/AC

AC = 15/1.96

AC = 7.65

AB² = AC² + BC²

AB² = 7.65² + 15²

AB² = 283.5

AB = √283.5

AB = 16.8

tan B = AC /BC

tanФ = 7.65/15

tanФ = 0.51

Ф = tan^-1(0.51)

B = 27°

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Read 2 more answers

A candy company claims that 20% of the candies in its bags are colored green. Steve buys 30 bags of 30 candies, randomly selects

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Answer:

The probability of Steve agreeing with the company’s claim is 0.50502.

Step-by-step explanation:

Let X denote the number of green candies.

The probability of green candies is, p = 0.20.

Steve buys 30 bags of 30 candies, randomly selects one candy from each, and counts the number of green candies.

So, n = 30 candies are randomly selected.

All the candies are independent of each other.

The random variable X follows a binomial distribution with parameter n = 30 and p = 0.20.

It is provided that if there are 5, 6, or 7 green candies, Steve will conclude that the company’s claim is correct.

Compute the probability of 5, 6 and 7 green candies as follows:

$P(X=5)={30\choose 5}(0.20)^{5}(1-0.20)^{30-5}=0.17228\\\\P(X=6)={30\choose 6}(0.20)^{6}(1-0.20)^{30-6}=0.17946\\\\P(X=7)={30\choose 7}(0.20)^{7}(1-0.20)^{30-7}=0.15328$

Then the probability of Steve agreeing with the company’s claim is:

P (Accepting the claim) = P (X = 5) + P (X = 6) + P (X = 7)

= 0.17228 + 0.17946 + 0.15328

= 0.50502

Thus, the probability of Steve agreeing with the company’s claim is 0.50502.

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