The length of AQ is 4, the length of WQ is 12, 4 divided by 12 can be simplified as 1 divided by 3 so the answer is A. 1/3
Answer:
Step-by-step explanation:
Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.
The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.
The system is
6h + 1d = 40
4h + 3d = 36
The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,
1d = 40 - 6h.
Now that we know what d equals, we can sub it into the second equation where we see a d. In order,
4h + 3d = 36 becomes
4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!
4h + 120 - 18h = 36 and
-14h = -84 so
h = 6.
That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:
1d = 40 - 6(6) and
d = 40 - 36 so
d = 4.
That means that each duck costs $4.
4/9 + (x-1) = 28/9 - (x-7x) + 1
4/9 + x - 1 = 28/9 - x + 7x + 1
-5/9 + x = 37/9 + 6x
-5x = 42/9
-5x = 4.6 (repeating 6)
x = -0.93 (repeating 3)
Hope this helps! ;)
Answer:
Step-by-step explanation:
The standard form equation of a circle is ...
(x -h)^2 +(y -k)^2 = r^2 . . . . . . . . . center at (h, k), radius r
Divide your given equation by 2 to put it into standard form:
(x +3)^2 +y^2 = 16
Comparing to the above, we see ...
The center point of the circle is (-3, 0); the radius is 4 units long.
