0.424 round each number to the place of the underlined digit. The underline number is 2.
2 answers:
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1) 2 1/3 is also equal to 7/3
4 1/5 is also equal to 21/5
you need to make the denominators the same so you have to find the lowest common multiple, which is 15 since both 5 and 3 can be times by to make 15
you need to also times the numerators by the number you're timesing the denominator by
7/3 x 5 = 35/15
21/5 x 3 = 63/15
now add those together
35/15 + 63/15 = 98/15
now just convert 98/15 back to a mixed fraction
98/15 = 6 8/15
the answer is..
I'll do the others in a different answer!!
Answer:
a) X is binomial with n = 10 and p = 0.3
Y is binomial with n = 10 and p = 0.7
b) The mean number of errors caught is 7.
The mean number of errors missed is 3.
c) The standard deviation of the number of errors caught is 1.4491.
The standard deviation of the number of errors missed is 1.4491.
Step-by-step explanation:
For each typing error, there are only two possible outcomes. Either it is caught, or it is not. The probability of a typing error being caught is independent of other errors. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
The standard deviation of the binomial distribution is:
10 word errors.
This means that
(a) If X is the number of word errors missed, what is the distribution of X ?
Human proofreaders catch 70 % of word errors. This means that they miss 30% of errors.
So for X, p = 0.3.
The answer is:
X is binomial with n = 10 and p = 0.3.
If Y is the number of word errors caught, what is the distribution of Y ?
Human proofreaders catch 70 % of word errors.
So for Y, p = 0.7.
The answer is:
Y is binomial with n = 10 and p = 0.7
(b) What is the mean number of errors caught?
The mean number of errors caught is 7.
What is the mean number of errors missed?
The mean number of errors missed is 3.
(c) What is the standard deviation of the number of errors caught?
The standard deviation of the number of errors caught is 1.4491.
What is the standard deviation of the number of errors missed?
The standard deviation of the number of errors missed is 1.4491.
Answer:
Step-by-step explanation:
This is a correct answer.