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1 year ago

What is the answer To 7/9 divided by 1/8

Mathematics

1 answer:

Nesterboy [21]1 year ago

6 0

56/9

To get to the answer you flip the second fraction 1/8 to 8/1. Then multiply 7/9 x 8/1

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2 years ago

C^2 = 27<br><br> Pls help me I’m doing my missing math work :,)

LekaFEV [45]

Answer c=5.196
c=sqrt(27)
c=5.196

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3 years ago

A researcher wants to estimate the percentage of all adults that have used the Internet to seek pre-purchase information in the

Lubov Fominskaja [6]

Answer:

The required sample size for the new study is 801.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

25% of all adults had used the Internet for such a purpose

This means that $\pi = 0.25$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

What is the required sample size for the new study?

This is n for which M = 0.03. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.25*0.75)}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.25*0.75}$

$\sqrt{n} = \frac{1.96\sqrt{0.25*0.75}}{0.03}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.25*0.75}}{0.03})^2$

$n = 800.3$

Rounding up:

The required sample size for the new study is 801.

4 0

2 years ago

An experiment consists of rolling a six-sided die to select a number between 1 and 6 and drawing a card at random from a set of

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<span>The event definition that corresponds to exactly one outcome of the experiment is that both numbers are 5s.</span>

5 0

2 years ago

Read 2 more answers

What is the sum of all of the perfect squares between

Nonamiya [84]

Answer:

(-138) is the answer.

Step-by-step explanation:

Perfect square numbers between 15 and 25 inclusive are 16 and 25.

Sum of perfect square numbers 16 and 25 = 16 + 25 = 41

Sum of the remaining numbers between 15 and 25 inclusive means sum of the numbers from 17 to 24 plus 15.

Since sum of an arithmetic progression is defined by the expression

$S_{n}=\frac{n}{2}[2a+(n-1)d]$

Where n = number of terms

a = first term of the sequence

d = common difference

$S_{8}=\frac{8}{2} [2\times 17+(8-1)\times 1]$

= 4(34 + 7)

= 164

Sum of 15 + $S_{8}$ = 15 + 164 = 179

Now the difference between 41 and sum of perfect squares between 15 and 25 inclusive = $41-179$

= -138

Therefore, answer is (-138).

7 0

2 years ago