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3 years ago

Is 2,000 meters are bigger than 20 kilometers

Mathematics

2 answers:

ra1l [238]3 years ago

8 0

I believe that is bigger

mixas84 [53]3 years ago

5 0

20 kilometers is bigger

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A sample of five words was randomly selected from a 200-page book. The average number of letters of the five words was calculate

Butoxors [25]

The answer would be A).

4 0

3 years ago

Read 2 more answers

Help me please I beg please but please

stealth61 [152]

Answer:

9. $\frac{1}{10}$ fraction.

10. $\frac{3}{10}$ fraction.

Step-by-step explanation:

In the given table, we get, Andrea hiked $\frac{2}{5}$ of the total trail, Jon hiked $\frac{1}{2}$ of the total trail and Callie hiked $\frac{4}{5}$ of the total trail.

9. Therefore, Jon hiked $(\frac{1}{2} - \frac{2}{5}) = \frac{5 - 4}{10} = \frac{1}{10}$ fraction than Andrea hiked.

10. Therefore, Callie hiked $(\frac{4}{5} - \frac{1}{2}) = \frac{8 - 5}{10} = \frac{3}{10}$ fraction than Jon hiked. (Answer)

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3 years ago

Write the following as an expression: How much water do I need to add to l liters of pure alcohol to obtain a solution of 45% al

vredina [299]

Answer:

see below

Step-by-step explanation:

amount of water w

l liter of pure alcohol = 100% alcohol

solution is 45 % percent alcohol

total amount of fluid is w+l

(w+l)( .45) = l*.100

Distribute

.45w + .45 l = 1l

.45 w = 1l - .45l

.45 w = .55l

w = .55l / .45

w =11/9 l

3 0

3 years ago

Which is the equation of a hyperbola with directrices at x = ±3 and foci at (4, 0) and (−4, 0)?

Alex Ar [27]

Answer:

$\frac{x^2}{12}-\frac{y^2}{4}=1$

Step-by-step explanation:

Since our foci are located on the x-axis, then our major axis is going to be the horizontal transverse axis of the hyperbola:

<u>Formula for hyperbola with horizontal transverse axis centered at origin</u>

<u /> $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$
Directrices -> $x=\pm\frac{a^2}{c}$
Foci -> $(\pm c,0)$ where $a^2+b^2=c^2$
$a>b$

Since we are given our directrices of $x=\pm3$ and foci of $(\pm4,0)$ , then we can set up the directrices equation to solve for $a^2$ :

$x=\pm\frac{a^2}{c}\\ \\\pm3=\pm\frac{a^2}{4}\\ \\12=a^2$

Now we can determine $b^2$ to complete our equation for the hyperbola:

$a^2+b^2=c^2\\\\12+b^2=4^2\\\\12+b^2=16\\\\b^2=4$

Therefore, our equation for our hyperbola is $\frac{x^2}{12}-\frac{y^2}{4}=1$

5 0

2 years ago

Three consecutive odd integers are such that the sum of the first and second is 31 less than 3 times the third. Find the integer

Otrada [13]

1st:x

2nd x+2

3rd: x+4

(x)+(x+2) = 3(x+4)-31

distribute

2x+2 = 3x+12-31

2x+2 =3x-19

subtract 2x from each side

2 = x-19

add 19 to each side

21 =x

Answer: 21,23,25

3 0

3 years ago