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Softa [21]
3 years ago
5

The vertices of ABC are A(-3,5), B(-2,3), and C(-5,3). If ABC is reflected across the y-axis to produce the image A'B'C', find t

he coordinate of the vertex C'.
Mathematics
1 answer:
Nat2105 [25]3 years ago
7 0

Answer:

C' =(5,3)

Step-by-step explanation:

Given

A = (-3,5)

B = (-2,3)

C = (-5,3)

Reflection across y-axis

Required

Find C'

For reflection across y-axis, the rule is:

(x,y) \to (-x,y)

So, the image of C is:

(-5,3) \to (-(-5),3)

(-5,3) \to (5,3)

Hence:

C' =(5,3)

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Blaire needs more than 616 total points on assignments in her math class to pass. She only has 224 points and needs to do some e
jek_recluse [69]

Answer: The answer is x >7

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56⋅x>616−224

56⋅x>616-224

Simplify :

56⋅x>392

56⋅x>392

Dividing by the variable coefficient :

x>

392

56

x>39256

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x>7

x>7

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56⋅x+224>616

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4 0
3 years ago
Student Produced Response - Calculator
faltersainse [42]

Answer:

\dfrac{a}{b}=0.75.

Step-by-step explanation:

If two equations a_1x+b_1y+c_1=0 and a_2x+b_2y+c_2=0 has infinitely many solutions, then

\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}

The given equations are

ax+by=10

3x+4y=20

It is given that the above system of equations has infinitely many solutions. So,

\dfrac{a}{3}=\dfrac{b}{4}=\dfrac{10}{20}

\dfrac{a}{3}=\dfrac{b}{4}=\dfrac{1}{2}

Now,

\dfrac{a}{3}=\dfrac{1}{2} and \dfrac{b}{4}=\dfrac{1}{2}

a=\dfrac{3}{2} and b=\dfrac{4}{2}

a=1.5 and b=2

So, a=1.5 and b=2.

Now,

\dfrac{a}{b}=\dfrac{1.5}{2}=0.75

Therefore, \dfrac{a}{b}=0.75.

5 0
3 years ago
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