We'll use the notation
for the principal value and
for all the values:

Part I


Part II. In our range we can write


Part III.

Part IV.


Answer:
14
Step-by-step explanation:
Its like a clock, except directly away from the six is not twelve, it's 13. That means the clock would have to have added two numbers for there to be a whole number facing the six.
Here's the link to the answer.. 69.08
Answer:
b
Step-by-step explanation:
only b has 10 didgets. it could be a since the didgets aren't very random, but then again, i think it's b
(X+3)^2+(X-2)^2=9................