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3 years ago

Explain how to write 5/3 as a product

1 answer:

3 0

You can make 5 into a fraction, 5/1, meaning there are 5 whole numbers, or simply just 5. You can use the unit fraction 1/3 to represent the 3 being the denominator.
When you mulitply fractions, you multiply straight across.
$\frac{5}{1} * \frac{1}{3} = \frac{5}{3}$

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Angle measure represented by 36.7 rotations counterclockwise

zhannawk [14.2K]

Answer:

13,212° or 73.4π radians

Step-by-step explanation:

Each rotation is 360° or 2π radians. So, 36.7 rotations is ...

36.7×360° = 13,212°

36.7×2π = 73.4π radians

7 0

3 years ago

1+-w2+9w and I need help cuz I’m on 76 and I’m sooo close help

Gnesinka [82]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Simplify :- 1 + - w² + 9w.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\large \sf1 + - w ^ { 2 } + 9 w$

Quadratic polynomial can be factored using the transformation $\sf \: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right)$ , where $\sf x_{1} and x_{2}$ are the solutions of the quadratic equation $\sf \: ax^{2}+bx+c=0$ .

$\large \sf-w^{2}+9w+1=0$

All equations of the form $\sf\:ax^{2}+bx+c=0$ can be solved using the quadratic formula: $\sf\frac{-b±\sqrt{b^{2}-4ac}}{2a}$ . The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$\large \sf \: w=\frac{-9±\sqrt{9^{2}-4\left(-1\right)}}{2\left(-1\right)} \\$

Square 9.

$\large \sf \: w=\frac{-9±\sqrt{81-4\left(-1\right)}}{2\left(-1\right)} \\$

Multiply -4 times -1.

$\large \sf \: w=\frac{-9±\sqrt{81+4}}{2\left(-1\right)} \\$

Add 81 to 4.

$\large \sf \: w=\frac{-9±\sqrt{85}}{2\left(-1\right)} \\$

Multiply 2 times -1.

$\large \sf \: w=\frac{-9±\sqrt{85}}{-2} \\$

Now solve the equation $\sf\:w=\frac{-9±\sqrt{85}}{-2}$ when ± is plus. Add -9 to $\sf\sqrt{85}$ .

$\large \sf \: w=\frac{\sqrt{85}-9}{-2} \\$

Divide -9+ $\sf\sqrt{85}$ by -2.

$\large \boxed{ \sf \: w=\frac{9-\sqrt{85}}{2}} \\$

Now solve the equation $\sf\:w=\frac{-9±\sqrt{85}}{-2}$ when ± is minus. Subtract $\sf\sqrt{85}$ from -9.

$\large \sf \: w=\frac{-\sqrt{85}-9}{-2} \\$

Divide $\sf-9-\sqrt{85}$ by -2.

$\large \boxed{ \sf \: w=\frac{\sqrt{85}+9}{2}} \\$

Factor the original expression using $\sf\:ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right)$ . Substitute $\sf\frac{9-\sqrt{85}}{2}$ for $\sf\:x_{1}$ and $\sf\frac{9+\sqrt{85}}{2}$ for $\sf\:x_{2}$ .

$\large \boxed{ \boxed {\mathfrak{-w^{2}+9w+1=-\left(w-\frac{9-\sqrt{85}}{2}\right)\left(w-\frac{\sqrt{85}+9}{2}\right) }}}$

Well, in the picture you inserted it says that it's 8th grade mathematics. So, I'm not sure if you have learned simplification with the help of biquadratic formula. So, if you want the answer simplified only according to like terms then your answer will be ⇨

$\large \sf \: 1 + - w {}^{2} + 9w \\ =\large \boxed{\bf \: 1 - {w}^{2} + 9w}$

This cannot be further simplified as there are no more like terms (you can use the biquadratic formula if you've learned it.)

4 0

2 years ago

Simplify as much as possible:<br> (7nm5o2) (-3m3o5)2

Yakvenalex [24]

Answer:

63m^11 no^12

Step-by-step explanation:

Dont know if thats o or and zero but I solve it by using o..if it was a zero then comment that so I can redo it anyways heres the explanation

(7nm^5 o^2) × (-3m^3 o^5)^2

7m^5 no^2) ×(-3m^3 o^5) ^2

(7m^5 no^2) × (3m^3 o^5)^2

7m^5 no^2 × (3m^3 o^5) ^2

7m^5 no^2 × 9m^6 o^10

63m^11 no^12

3 0

3 years ago

Can someone please explain to me how I'm supposed to solve 2x+y=12? Like step by step solving?

Ne4ueva [31]

Well, first put the function in slop-intercept form (y = mx + b). 2x + y = 12, y - 2x = 12 - 2x, y = -2x + 12. So y = -2x + 12 is the slope-intercept form. Then graph the function to solve for all possible solutions to the function. In y = mx + b, m is the slope and b is the y intercept. In y = -2x + 12, m equals -2, so the slope is -2, and b equals 12, so 12 is the y intercept. Make a point on the y intercept at y = 12. The slope is -2, or -2/1. The graph will be sloping downward. From the point at y = 12, move down two units and to the right one unit and make another point. Then from this new point move down two units and to the right one unit and make another point, and so on. Then to extend the graph in the other direction, start at the point y = 12 and move two units up and one unit to the right and make a point there. Then from this new point move two units up and one unit to the right and make another point there, and so on.

3 0

2 years ago

What is the rule for 5,6.7,8 and the other coulum 10,12,14,20

zavuch27 [327]

5 rule 10 ruled to the secondly power 48384

4 0

3 years ago