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4 years ago

I need help to find X

Mathematics

1 answer:

Liono4ka [1.6K]4 years ago

6 0

Step-by-step explanation:

trigonometric functions such as sin cos and tan will help u solve this

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Find the linear equation of the plane through the origin and the points (5,2,2) and (6,−1,1). equation:

Aleks [24]

The cross of the position vectors is
.. [5, 2, 2] × [6, -1, 1] = [4, 7, -17] . . . . . the normal vector of the desired plane

Since the origin is a point in the plane, its equation can be written as
.. 4x +7y -17z = 0

3 0

4 years ago

99 points help SHOW YOUR WORK Q+B=13. When B+3=0

belka [17]

Q+B=13. When B+3=0

You have 2 separate equations.

First solve the 2nd equation for B:

B +3 = 0

Subtract 3 from both sides:

B +3 - 3 = 0-3

Simplify:

B = -3

Now we have a value for B, we can replace b with -3 in the first equation and solve for Q:

Q + -3 = 13

Add 3 to each side:

Q + -3 + 3 = 13+3

Simplify:

Q = 16

So you have Q = 16 and B = -3

7 0

3 years ago

Read 2 more answers

What are 3 ways that have the same value as 75% of 96

stealth61 [152]

Step-by-step explanation:

The three ways by which we can find the 75% of 96 -

1 ) Simply multiply and extract 75% of 96 as follows -

= 75/100 * 96

= 72

2) We can write 75% as 3/4 of the total so if we multiply 3/4 with 96 we

will get 75% of 96

= 3/4 * 96

= 72

3) We can also get 75% of 96 by taking out the 1/4 rd of 96 and subtracting

from 96 we get 75% of 96

= 96 - (1/4 * 96)

= 96 - 24

= 72

4 0

4 years ago

Simplify<br> 3x + 5 + 2x - 4

77julia77 [94]

Answer:

5x+1

Step-by-step explanation:

4 0

3 years ago

Help me please!!!!!! It’s math btw.

FrozenT [24]

1. The 5/65 can be simplified, the a³ moves to the denominator, and bc is canceled from the numerator and denominator.
$\frac{5a^3 bc^2}{65 a^4 bc} = \frac{c}{13a}$

2. The 10/125 can be simplified, the a³ moves to the denominator, and bc is canceled from the numerator and denominator.
$\frac{10a^3bc^2}{125a^4bc} = \frac{2c}{25a}$

3. The 65/5 simplifies, the a³ moves to the numerator, and bc is canceled from the numerator and denominator.
$\frac{65a^4 bc^2}{5a^3 bc} = 13ac$

4. The 10/130 simplifies, the b² cancels out in the numerator and denominator, and the $c^4$ moves to the numerator.
$\frac{10b^2 c^5}{130a^4b^2c^4} = \frac{c}{13a^4}$

5. The 10/130 simplifies, the b² cancels out in the numerator and denominator, the $a^4$ moves to the numerator, and the $c^4$ moves to the numerator.
$\frac{10a^5b^2c^5}{130a^4b^2c^4} = \frac{ac}{13}$

I believe the only expression that simplifies to $\frac{c}{13a}$ is the first one.

7 0

3 years ago