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scoray [572]
3 years ago
9

Sara drives 72 miles on 3.2 gallons of gas. She uses this information to calculate how many miles per gallon she can drive. Usin

g this result, how many miles can Sara drive on 12.3 gallons of gas? ​
Mathematics
1 answer:
nordsb [41]3 years ago
8 0

Answer:

276.75 miles

Step-by-step explanation:

12.3/3.2 × 72 = 276.75 miles

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When solving the equation such as 2/3x = 4/5 , why would you multiply both sides of the equation by the reciprocal of 2/3 ?
barxatty [35]
Answer: Well you’re solving for “x,” so you’ll need to isolate this variable. This means we need to “get rid of” the fraction 2/3 that is attached to it. The faction is attached by the operation multiplication, so to remove it we must divide it on both sides. And division with fractions requires the reciprocal. (Try watching an explanation if you’re confused on why division requires reciprocals).
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3 years ago
I need to understand this math.
melamori03 [73]
Just think of for example 6x4=24 so the Division problom would be 24 divided by 4 or 6 the answer would be 6 or 4

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3 years ago
Generate two equivalent fractions for each fraction. Use fraction tikes or number lines.<br> 1/3
Romashka [77]
Equivealent= like 

6/18, 5/15
3/9, 2/6 
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3 years ago
Margo added three multi-digit decimal numbers. The first number was 5.19. The second number was 10 times the first number. The t
Anika [276]

Answer: 576.09

Step-by-step explanation:

First number = 5.19.

The second number was 10 times the first number which will be:

= 5.19 × 10

= 51.9

The third number was 10 times the second number. Thus will be:

= 51.9 × 10

= 519

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3 years ago
Given that f(x) = x + 3<br> a) Find f(2)
Nataly_w [17]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

In the above question, it is given that :

\qquad \sf  \boxed{ \sf f(x) =  \frac{x + 3}{2} }

A.) Find f(2) :

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{2 + 3}{2}

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{5}{2}

or

\qquad \sf  \dashrightarrow \: f(2) = 0.5

B.) Find { \sf {f}^{-1}(x) } :

\qquad \sf  \dashrightarrow \: let \: y = f (x)

so, we can write it as :

\qquad \sf  \dashrightarrow \: y =  \dfrac{x + 3}{2}

\qquad \sf  \dashrightarrow \: 2y = x + 3

\qquad \sf  \dashrightarrow \: x = 2y - 3

Now, put x = { \sf {f}^{-1}(x) }, and y = x and we will get our required inverse function ~

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3

C.) Find { \sf {f}^{-1}(12) } :

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33

7 0
1 year ago
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