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olga_2 [115]
3 years ago
10

What if every minute was 30 seconds. How many minutes would be in 1 hour. How many minutes would be 24 hours. How many minutes d

oes it take to make a month. How many minutes would it take to make a Year?
Mathematics
1 answer:
DENIUS [597]3 years ago
5 0

Answer:

30 minutes

Step-by-step explanation:

if every minute was 30 seconds, you just cut everything in half. so, if an hour is 60 minutes, the new number would just be 30 minutes.

i hope this helps!

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The average age of all students at a certain college is 22 years and the standard deviation is 2 years. What is the probability
Marianna [84]

Answer:

The probability that the average age of a randomly selected sample of 100 students will be less than 21.8 years is 0.159

Step-by-step explanation:

According to the given data we have the following:

mean = μ= 22

standard deviation = σ = 2

n = 100

μx = 22

σx=σ/√n=2/√100=0.2

Therefore, P( x < 21.8)=P(x-μx)/σx<(21.8-22)/0.2

=P(z<-1)

= 0.159

The probability that the average age of a randomly selected sample of 100 students will be less than 21.8 years is 0.159

3 0
4 years ago
Which of the binomials below is a factor of this trinomial?
Tamiku [17]
None of those answers are correct sadly.
8 0
3 years ago
Read 2 more answers
Shania drove on the interstate for 310 miles without stopping. If she traveled at a constant rate and the trip took her 5 hours,
sp2606 [1]

Answer:

62 miles per hour/62 mph

Step-by-step explanation:

Shania drives at a CONSTANT rate, which means in the 5 hours it took her to drive, each hour she drove the same amount.

So we need to do 310 miles in 5 hours, which is:

310/5

Solving this, we get:

62

The answer is 62 miles per hour.

Happy learning!

4 0
3 years ago
Read 2 more answers
What is the area of a square with a side of 8x^7 y^3
sukhopar [10]
Area of a square with side s is \sf{s^2}

In your question, the side or s is: \sf{8x^7y^3}

And so the area of a square with that side length would be:

\sf{(8x^7y^3)^2}

And using this formula: \sf{(a^b)^c =a^{b\times c}}

We get that the area is:

\sf{(8x^7y^3)^2 = 8^2 x^{7\times 2} y^{3\times 2}}

And simplifying that we get the final answer as:

\huge{\boxed{\bf{Area=64x^{14}y^{6}}}}
4 0
3 years ago
The length of a rectangle is three inches more than the width. the area of the rectangle is 180 inches. find the width of the re
ch4aika [34]

We have a rectangle with length L that is 3 inches more than the width W. Then we can write this as:

L=W+3

The area of the rectangle is 180 square inches.

We have to find the width W.

As the area is equal to the product of the length and the width, we can write this equation and solve for W as:

\begin{gathered} A=180 \\ L\cdot W=180 \\ (W+3)\cdot W=180 \\ W^2+3W=180 \\ W^2+3W-180=0 \end{gathered}

We have a quadratic equation. The roots of this equation will be the mathematical solutions.

We can find the roots using the quadratic formula:

\begin{gathered} W=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ W=\frac{-3\pm\sqrt[]{3^2-4\cdot1\cdot(-180)}}{2\cdot1} \\ W=\frac{-3\pm\sqrt[]{9+720}}{2} \\ W=\frac{-3\pm\sqrt[]{729}}{2} \\ W=\frac{-3\pm27}{2} \\ W_1=\frac{-3-27}{2}=-\frac{30}{2}=-15 \\ W_2=\frac{-3+27}{2}=\frac{24}{2}=12 \end{gathered}

The solutions are W = -15 and W = 12.

The first one is not valid, as W has to be greater than 0.

Then, the solution to our problem is W = 12 in.

Answer: the width is W = 12 inches.

6 0
1 year ago
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