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3 years ago

1)When adding two negative numbers, _________ the absolute value of the numbers and keep the negative sign.

Mathematics

2 answers:

rosijanka [135]3 years ago

8 0

1) add.

for example -1 + -2 = - (||-1| + |-2||), which is -(1+2) or -3

2) subtract

for example 4 + -7 = -(||-7| + |4||), which is - |7 - 4| or -3

3) change
for example 3 - (- 2) = 3 + 2

tresset_1 [31]3 years ago

7 0

Answer: first add then stubract then you chanege it

Step-by-step explanation:

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egoroff_w [7]

Answer:

(1, 3)

Step-by-step explanation:

You are given the h coordinate of the vertex as 1, but in order to find the k coordinate, you have to complete the square on the parabola. The first few steps are as follows. Set the parabola equal to 0 so you can solve for the vertex. Separate the x terms from the constant by moving the constant to the other side of the equals sign. The coefficient HAS to be a +1 (ours is a -2 so we have to factor it out). Let's start there. The first 2 steps result in this polynomial:

$-2x^2+4x=-1$ . Now we factor out the -2:

$-2(x^2-2x)=-1$ . Now we complete the square. This process is to take half the linear term, square it, and add it to both sides. Our linear term is 2x. Half of 2 is 1, and 1 squared is 1. We add 1 into the set of parenthesis. But we actually added into the parenthesis is +1(-2). The -2 out front is a multiplier and we cannot ignore it. Adding in to both sides looks like this:

$-2(x^2-2x+1)=-1-2$ . Simplifying gives us this:

$-2(x^2-2x+1)=-3$

On the left we have created a perfect square binomial which reflects the h coordinate of the vertex. Stating this binomial and moving the -3 over by addition and setting the polynomial equal to y:

$-2(x-1)^2+3=y$