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MrRa [10]
3 years ago
9

The quotient of b and 2 minus 4 is at least 26. I need this ASAP

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
3 0

For this case we must express the following expression algebraically:

<em>"The quotient of b and 2 minus 4 is at least 26"</em>

So we have to:

The quotient of b and 2 minus 4, is represented as:\frac {b} {2-4}

We have different signs subtracted and the sign of the major is placed:

\frac {b} {- 2}

Thus, the expression is written as:

\frac {b} {2-4} \geq26\\\frac {b} {- 2} \geq26\\- \frac {b} {2} \geq26

ANswer:

\frac {b} {2-4} \geq26

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The friend is wrong - According to the Pythagorean Theorm, if c is the hypotenuse and a and b are opposite sides then  c^{2} = a^{2}  +  b^{2} 
if c=65 inches, a=16 inches and b = 63 inches, then
 65^{2} =16 ^{2} +  63^{2}
right hand side of the equation = 256 + 3969 = 4225
left hand side of the equation = 65^{2}= 4225
So we see, left hand side = right hand side
Hence the theorm is proved.




5 0
3 years ago
Suppose that an object whose is 10th weighs 50 N find the weight of an object whose is 6 kg
Nady [450]
Weight is another term for the force from mass multiplied by acceleration due to gravity, the equation being expressed as f = ma, being force, mass, and acceleration respectively.

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Plug it into the equation f = ma

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3 years ago
What is the answer to 16x8
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Answer is: 16x8 = 128

6 0
3 years ago
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A traffic light at a certain intersection is green 50% of the time, yellow 10% of the time, and red 40% of the time. A car appro
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Answer:

6.4\times 10^{-5} = 0.000064 = 0.0064\%.

Step-by-step explanation:

Probability that the car encounters a green light on the first day: 50 \% = 0.5.

To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be

(0.5) \times 0.5 = 0.25.

  • Condition is met on the first two days and green light on the third day: (0.5 \times 0.5) \times 0.5 = 0.125.
  • Condition is met on the first three days and green light on the fourth day:   (0.5 \times 0.5 \times 0.5) \times 0.5.

To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be (0.5 \times 0.5 \times 0.5 \times 0.5) \times 0.1 = 0.5^{4} \times 0.1.

To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. (0.5^{4} \times 0.1) \times 0.4

  • Seventh day: (0.5^{4} \times 0.1 \times 0.4 ) \times 0.4
  • Eighth day: (0.5^{4} \times 0.1 \times 0.4^2 ) \times 0.4
  • Ninth day: (0.5^{4} \times 0.1 \times 0.4^3 ) \times 0.4
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The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: 0.5^{4} \times 0.1 \times 0.4^{5} = 6.4\times 10^{-5} = 0.000064 = 0.0064\%.

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3 years ago
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My mystery number has 5 tens and 29 ones?
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