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3 years ago

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The time needed to roast a chicken depends on its weight. Allow at least 20min/lb for a chicken weighing as much as 6 lb. Allow

at least 15 min/lb for a chicken wieghing more than 6 lb.
a. Write two inequalities to represent the time needed to roast a chicken.

b. Graph the inequalities.

1 answer:

Aleksandr [31]3 years ago

8 0

B. Graph the inequalities

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bulgar [2K]

The answer is b bc it’s all real numbers since it won’t stop

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2 years ago

What is 3.30 divided by -2.00? Show work.

coldgirl [10]

Answer:

<h2>1.65</h2>

Step-by-step explanation:

$\frac{3.3}{-2}\\\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}\\=-\frac{3.3}{2}\\\\\mathrm{Divide\:the\:numbers:}\:\\\frac{3.3}{2}=1.65$

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2 years ago

In a particular month, Ezhil spent one-fifth of her salary on shopping. Two-fifth of the remaining she gave to her sister. If sh

Oxana [17]

Answer:

$Salary = Rs23000$

Step-by-step explanation:

Given

$Shopping = \frac{1}{5}$

$Sister = \frac{2}{5}R$

$Left over = Rs11,040$

Required

Her salary in that month

Given that she spent $\frac{1}{5}$ of her salary on shopping, this implies that she has $\frac{4}{5}$ of her salary left

From what's left, she gave her sister $\frac{2}{5}$

This means she gave her sister $\frac{2}{5} * \frac{4}{5}$

Sister = $\frac{8}{25}$

Calculating a fraction of what's left

$Left over = 1 -Shopping - Sister$

$Left over = 1 - \frac{1}{5}- \frac{8}{25}$

$Left over = \frac{25 - 5 - 8}{25}$

$Left over = \frac{12}{25}$

Recall that she has Rs11,040

This means that

$\frac{12}{25} of Salary = Rs11,040$

Multiply both sides by $\frac{25}{12}$

$\frac{12}{25} * \frac{25}{12} * Salary = Rs11,040 * \frac{25}{12}$

$Salary = Rs11,040 * \frac{25}{12}$

$Salary = \frac{Rs276000}{12}$

$Salary = Rs23000$

Hence, her salary for that month was Rs23000

5 0

2 years ago

Read 2 more answers

If an open box has a square base and a volume of 115 in.3 and is constructed from a tin sheet, find the dimensions of the box, a

Karolina [17]

Let h = height of the box,
x = side length of the base.

Volume of the box is $V=x^{2} h = 115$ .
So $h = \frac{115}{ x^{2} }$

Surface area of a box is S = 2(Width • Length + Length • Height + Height • Width).
So surface area of the box is
$S = 2( x^{2} + hx + hx) \\ = 2 x^{2} + 4hx \\ = 2 x^{2} + 4( \frac{115}{ x^{2} } )x$
$= 2 x^{2} + \frac{460}{x}$
The surface are is supposed to be the minimum. So we'll need to find the first derivative of the surface area function and set it to zero.

$S' = 4x- \frac{460}{ x^{2} } = 0$
$4x = \frac{460}{ x^{2} } \\ 4x^{3} = 460 \\ x^{3} = 115 \\ x = \sqrt[3]{115} = 4.86$
Then $h= \frac{115}{4.86^{2}} = 4.87$
So the box is 4.86 in. wide and 4.87 in. high.

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2 years ago

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Someone help me please

lina2011 [118]

Answer:

-13, 0.4,7 its the 4th one

Step-by-step explanation:

3 0

2 years ago