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Sholpan [36]
3 years ago
9

The time needed to roast a chicken depends on its weight. Allow at least 20min/lb for a chicken weighing as much as 6 lb. Allow

at least 15 min/lb for a chicken wieghing more than 6 lb.
a. Write two inequalities to represent the time needed to roast a chicken.

b. Graph the inequalities.
Mathematics
1 answer:
Aleksandr [31]3 years ago
8 0
B. Graph the inequalities
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7,4,9,8,4,4,6,6 mean,mode,median, and range
skad [1K]

Answer:

Mean: 6    Mode: 4   Median: 6    Range:5

Brainliest please :)

5 0
2 years ago
Read 2 more answers
Julianne opens a dance studio. Her start-up costs for the building, advertising, and supplies $52,000. Each day, she spends $650
amid [387]

<u>Answer-</u>

The equation is 960d-650d = 52000 and Julianne will begin making a profit after 168 days.

<u>Solution-</u>

Julianne's start-up cost = $52,000,

Each day, she spends = $650,

and she earns = $960 per day,

If 'd' is the number of days to overcome the start-up and daily operation cost, then  

total operation cost of d days = $650d and  

total student lesson fees earned in d days = $960d

∴ The equation to represent the situation is,

960d-650d = 52000

∴ Julianne will begin making a profit,

\Rightarrow 960d-650d \geq 52000

\Rightarrow 310d \geq 52000

\Rightarrow d \geq \frac{52000}{310} =167.74 \approx168(ans)





8 0
2 years ago
If f(x) = 3 ^ x - 4 what is f(- 2) ?​
Karolina [17]

Answer:

-35/9

Step-by-step explanation:

(3^-2)-4

1/9-4

-35/9

8 0
2 years ago
Find the volume of this the sphere round to the nearest tenth 7in [?]in*3
Lyrx [107]

Answer:

1436.8

Step-by-step explanation:

4/3×π×7³

= 1372π/3

≈ 1436.8

Answered by GAUTHMATH

5 0
2 years ago
Mason, a hardwood flooring installer, needs to calculate the amount of hardwood flooring needed to cover a floor that's 33⁄4 yar
Aleksandr-060686 [28]

Answer:

20 5/8 yd^2

Step-by-step explanation:

width = 3 3/4 yd

length = 5 1/2 yd

First change both measurements to fractions.

3 3/4 = 3 + 3/4 = 12/4 + 3/4 = 15/4

5 1/2 = 5 + 1/2 = 10/2 + 1/2 = 11/2

area = length * width

area = 15/4 yd * 11/2 yd

area = (15 * 11)/(4 * 2) yd^2

area = 165/8 yd^2

165/8 = 20 remainder 5

area = 20 5/8 yd^2

3 0
3 years ago
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