The tape diagram should have one box for $5, 121 as the total. And some more boxes where the value is 14.50. Hope this helps!
Answer:
the answer is 16 hours
Step-by-step explanation:
i just multiplied 12(the amount he gets from tutoring) and multiplied it by different numbers to see which one gets him past $190
The answer to, Is the Triangle with side lengths of 10 in., 24 in., and 26 in, a right triangle is: Yes. For right triangles, the sum of the squares of the shorter sides is equal to the square of the longer side. Thus, this is a right triangle if 10^2+24^2=26^2. Expanding these squares, we have 100+576=676, which is true. Thus, the triangle is right.
The <em>second order</em> polynomial that involves the variable <em>x</em> (border inside the rectangle) and associated to the <em>unshaded</em> area is x² - 62 · x + 232 = 0.
<h3>How to derive an expression for the area of an unshaded region of a rectangle</h3>
The area of a rectangle (<em>A</em>), in square inches, is equal to the product of its width (<em>w</em>), in inches, and its height (<em>h</em>), in inches. According to the figure, we have two <em>proportional</em> rectangles and we need to derive an expression that describes the value of the <em>unshaded</em> area.
If we know that <em>A =</em> 648 in², <em>w =</em> 22 - x and <em>h =</em> 40 - x, then the expression is derived below:
<em>A = w · h</em>
(22 - x) · (40 - x) = 648
40 · (22 - x) - x · (22 - x) = 648
880 - 40 · x - 22 · x + x² = 648
x² - 62 · x + 232 = 0
The <em>second order</em> polynomial that involves the variable <em>x</em> (border inside the rectangle) and associated to the <em>unshaded</em> area is x² - 62 · x + 232 = 0. 
To learn more on polynomials, we kindly invite to check this verified question: brainly.com/question/11536910