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QveST [7]
3 years ago
12

Solve n for the following preportion :

7D%7Bn%7D%20" id="TexFormula1" title=" \frac{3}{5} = \frac{12}{n} " alt=" \frac{3}{5} = \frac{12}{n} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Gemiola [76]3 years ago
5 0
N=20




3 times 4 is 12. Anything u multiple the top u multiple the bottom. So 5 times 4 is 2
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If sin A = 3/8, find the value of cosec A - sec A.​
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Answer:

\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}

Step by step explanation:

\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies  1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\

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\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}

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How Long will it take each student plan to be paid down to $1000?
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The corresponding answers for each student plan are:

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Learn more: brainly.com/question/14355665

4 0
2 years ago
Sally is 1 year older than 3 times the age of joe.Chirs is 5 years younger than 6 times the age of joe.If sally and Chris are th
Sav [38]
S = sally C = Chris J = Joe
sally is one year older than 3 times the age of joe, so
s = 3j + 1
chris is 5 years younger than 6 times the age of jo, so
c = 6j - 5
sally and chris are the same age so
s = c so
3j + 1 = 6j - 5
-3j -3j
1 = 3j - 5
+5 +5
6 = 3j or
3j = 6
3j/3 = 6/3
j = 2

check
s = c
3(2) +1 = 6(2) - 5
6 + 1 = 12 - 5
7 = 7 correct✅
7 0
3 years ago
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