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xxMikexx [17]
3 years ago
11

The area of a circular sun spot is growing at a rate of 1,200 km2/s.

Mathematics
1 answer:
Tpy6a [65]3 years ago
8 0
A)

\bf \textit{area of a circle}\\\\
A=\pi r^2
\\\\\\
\cfrac{dA}{dt}=\pi \cdot 2r\cfrac{dr}{dt}\implies \cfrac{dA}{dt}=2\pi r\cfrac{dr}{dt}\implies \cfrac{\frac{dA}{dt}}{2\pi r}=\cfrac{dr}{dt}\\\\
-----------------------------\\\\
\left. \cfrac{dr}{dt}  \right|_{r=3000}\implies \cfrac{1200}{2\pi \cdot 3000}=\cfrac{dr}{dt}\\\\

B)

\bf A=\pi r^2\qquad A=490000\implies 490000=\pi r^2\implies \sqrt{\cfrac{490000}{\pi }}=r
\\\\\\
\left. \cfrac{dr}{dt}  \right|_{r=\sqrt{\frac{490000}{\pi }}}\implies \cfrac{1200}{2\pi \cdot \sqrt{\frac{490000}{\pi }}}=\cfrac{dr}{dt}

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<u>First, we have to find </u>m<u>, the slope. We can use the slope equation to get this.</u>

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