Answer:
First find the hypotenuse of the small triangle then use that value as the base of the upper triangle. Evaluate the equation formed with the “x"
Given:
'a' and 'b' are the intercepts made by a straight-line with the co-
ordinate axes.
3a = b and the line pass through the point (1, 3).
To find:
The equation of the line.
Solution:
The intercept form of a line is
...(i)
where, a is x-intercept and b is y-intercept.
We have, 3a=b.
...(ii)
The line pass through the point (1, 3). So, putting x=1 and y=3, we get



Multiply both sides by a.

The value of a is 2. So, x-intercept is 2.
Putting a=2 in
, we get


The value of b is 6. So, y-intercept is 6.
Putting a=2 and b=6 in (i), we get

Therefore, the equation of the required line in intercept form is
.
Answer:
1/2
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
The slope (m) can be found using the formula ...
m = ∆y/∆x = (y2 -y1)/(x2 -x1)
= (1 -(-5))/(4 -1) = 6/3
m = 2
The slope of the line is 2.