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serious [3.7K]
3 years ago
13

A car travels 2.83 km in the x-direction, then turns left 65.3 ◦ to the original direction and travels an additional distance of

3.38 km. Calculate the x component of the car’s net displacement. Let : d1 = 2.83 km , θ = 65.3 ◦ , and d2 = 3.38 km . Answer in units of km
Mathematics
1 answer:
umka21 [38]3 years ago
4 0

Answer:

  4.24 km

Step-by-step explanation:

The x-component of the displacement after the turn is ...

  d2·cos(θ) = (3.38 km)cos(65.3°) ≈ 1.41239 km

Adding this to the displacement before the turn, we have ...

  x-component of displacement = 2.83 km + 1.41 km = 4.24 km

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From the information given we know that the price they can sell cakes is given by the function p=580-10x, where x is the number of cakes sold per day.

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TR=(580-10x)\cdot x\\TR=580x-10x^2

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MR=\frac{d}{dx}(580x-10x^2) \\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\MR=\frac{d}{dx}\left(580x\right)-\frac{d}{dx}\left(10x^2\right)\\\\MR=580-20x

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The Marginal Cost (MC) function is the derivative of the cost function and is given by

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We know that the total cost function of the company is given by C=(30+5x)^2, which it is equal to

\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2\\a=30,\:\:b=5x\\\\\left(30+5x\right)^2=30^2+2\cdot \:30\cdot \:5x+\left(5x\right)^2=25x^2+300x+900\\\\C=25x^2+300x+900

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