D
is the answer because 6 is lonely but on new equation 13 and 6 disspapeared so the added answer is 19 which is letter D.
Answer:
∠1 ≅ ∠2 ⇒ proved down
Step-by-step explanation:
#12
In the given figure
∵ LJ // WK
∵ LP is a transversal
∵ ∠1 and ∠KWP are corresponding angles
∵ The corresponding angles are equal in measures
∴ m∠1 = m∠KWP
∴ ∠1 ≅ ∠KWP ⇒ (1)
∵ WK // AP
∵ WP is a transversal
∵ ∠KWP and ∠WPA are interior alternate angles
∵ The interior alternate angles are equal in measures
∴ m∠KWP = m∠WPA
∴ ∠KWP ≅ ∠WPA ⇒ (2)
→ From (1) and (2)
∵ ∠1 and ∠WPA are congruent to ∠KWP
∴ ∠1 and ∠WPA are congruent
∴ ∠1 ≅ ∠WPA ⇒ (3)
∵ WP // AG
∵ AP is a transversal
∵ ∠WPA and ∠2 are interior alternate angles
∵ The interior alternate angles are equal in measures
∴ m∠WPA = m∠2
∴ ∠WPA ≅ ∠2 ⇒ (4)
→ From (3) and (4)
∵ ∠1 and ∠2 are congruent to ∠WPA
∴ ∠1 and ∠2 are congruent
∴ ∠1 ≅ ∠2 ⇒ proved
Answer:

Step-by-step explanation:
Given


Required [Missing from the question]
G(T(x))
We have:

This implies that:

Substitute: 
![G(T(x)) = 3[9(x + 6.9)]](https://tex.z-dn.net/?f=G%28T%28x%29%29%20%3D%203%5B9%28x%20%2B%206.9%29%5D)
Open bracket

Answer:
Mr. Chang will have 15714.90 dollars.
Step-by-step explanation:
p = 650
r = 
Number of periods or n = 
Future value formula is : ![p[\frac{(1+r)^{n}-1}{r} ]](https://tex.z-dn.net/?f=p%5B%5Cfrac%7B%281%2Br%29%5E%7Bn%7D-1%7D%7Br%7D%20%5D)
Putting the values in formula we get;
![650[\frac{(1+0.0195)^{20}-1}{0.0195} ]](https://tex.z-dn.net/?f=650%5B%5Cfrac%7B%281%2B0.0195%29%5E%7B20%7D-1%7D%7B0.0195%7D%20%5D)
= $15714.90
Hence, Mr. Chang will have 15714.90 dollars.