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Mila [183]
3 years ago
13

Your company has an external database of payment information that they wish to populate in Salesforce. They have decided to use

Lightning connect & External objects to fulfill this requirement. If they wish to link this external object to Opportunities, which kind of relationship will need to be created?
A. Indirect lookup
B. External lookup
C. Master-‐detail
D. Lookup
Computers and Technology
1 answer:
Anettt [7]3 years ago
3 0

Answer:

Option A i.e., Indirect Lookup is the correct option.

Explanation:

In the following statement, a company has a database that is external information of the payment then, they desire to increase the population. Then, they determine that if they use External object and also they use Lightning connect to accomplish the following requirements. Then, finally, they desire to establish an indirect lookup relationship.

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Write a copy constructor for carcounter that assigns origcarcounter.carcount to the constructed object's carcount. sample output
Drupady [299]

#include <iostream>

using namespace std;

class CarCounter {

  public:

     CarCounter();

     CarCounter(const CarCounter& origCarCounter);

     void SetCarCount(const int count) {

         carCount = count;

     }

     int GetCarCount() const {

         return carCount;

     }

  private:

     int carCount;

};

CarCounter::CarCounter() {

  carCount = 0;

  return;

}

CarCounter::CarCounter(const CarCounter &p){

carCount = p.carCount;

}

void CountPrinter(CarCounter carCntr) {

  cout << "Cars counted: " << carCntr.GetCarCount();

  return;

}

int main() {

  CarCounter parkingLot;

  parkingLot.SetCarCount(5);

  CountPrinter(parkingLot);

  return 0;

}

Sample output:  

Cars Counted: 5

8 0
4 years ago
Read 2 more answers
Get two positive integers from the user. Write code to multiply the two numbers together using only addition or subtraction. You
padilas [110]

Answer:

number1 = int(input("Enter the first number: "))

number2 = int(input("Enter the second number: "))

result = 0

for i in range(number1):

   result += number2

print(str(result))

Explanation:

Ask the user for two numbers

Initialize result as 0 to hold the multiplication of the numbers

Create a for loop that iterates "number1" times. In each iteration, add number2 to the result.

When the loop is done, print the result

8 0
4 years ago
Write a setInterval() function that increases the count by 1 and displays the new count in counterElement every 300 milliseconds
Alina [70]

Answer:

  1. var count = 0;
  2. var counterElement = document.getElementById("counter");
  3. counterElement.innerHTML = count;
  4. var a = setInterval(
  5.    function(){  
  6.        count++;
  7.        counterElement.innerHTML = count;
  8.        if(count == 5){
  9.            clearInterval(a);
  10.        }
  11.    }
  12.        , 300);

Explanation:

The solution code is given from Line 6 - 15.  

setInterval function is a function that will repeatedly call its inner function for an interval of time. This function will take two input, an inner function and the interval time in milliseconds.  

In this case, we define an inner function that will increment count by one (Line 8) and then display it to html page (Line 9). This inner function will repeatedly be called for 300 milliseconds. When the count reaches 5, use clearInterval to stop the innerFunction from running (Line 11 - 13).  

8 0
3 years ago
In this lab, you use the flowchart and pseudocode found in the figures below to add code to a partially created C++ program. Whe
never [62]

Answer:

The equivalent program in C++:

#include<iostream>

#include <sstream>

using namespace std;

int main(){

   string Score, Rank;

   cout<<"Enter student score and class rank: ";

   cin>>Score>>Rank;

   int testScore = 0, classRank = 0;

   stringstream sstream(Score);

   sstream>>testScore;

   

   stringstream tream(Rank);

   tream>>classRank;

   

   if (testScore >= 90){

       if(classRank >=25){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else if(testScore >= 80){

       if(classRank >=50){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else if(testScore >= 70){

       if(classRank >=75){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else{cout<<"Reject";}

   return 0;

}

Explanation:

This declares Score and Rank as string variables

   string Score, Rank;

This prompts the user for score and class rank

   cout<<"Enter student score and class rank: ";

This gets the user input

   cin>>Score>>Rank;

This declarees testScore and classRank as integer; and also initializes them to 0

   int testScore = 0, classRank = 0;

The following converts string Score to integer testScore

<em>    stringstream sstream(Score);</em>

<em>    sstream>>testScore;</em>

The following converts string Rank to integer classRank

   stringstream tream(Rank);

   tream>>classRank;

The following conditions implement the conditions as given in the question.    

If testScore >= 90

<em>    if (testScore >= 90){</em>

If classRank >=25

<em>        if(classRank >=25){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    } ---</em>

If testScore >= 80

<em>    else if(testScore >= 80){</em>

If classRank >=50

<em>        if(classRank >=50){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    }</em>

If testScore >= 70

<em>    else if(testScore >= 70){</em>

If classRank >=75

<em>        if(classRank >=75){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    }</em>

For testScore less than 70

<em>    else{cout<<"Reject";}</em>

<em />

3 0
3 years ago
Paul is a chemical engineer working with large storage tanks of chemicals. Working from home using a program on his computer, he
gregori [183]
A pressure regulator application on his computer or a station nearbye
7 0
3 years ago
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