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sergey [27]
3 years ago
12

Draw a model to show 6 times as much as3

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
8 0

6x*3 may be an answer but I am not sure right this moment but you can try.


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X² + y² if x = 7 and y = 5. What is the solution to this??
Shtirlitz [24]

Hey there!

x^2 + y^2

= 7^2 + 5^2

= 7 * 7 + 5 * 5

= 49 + 25

= 74


Therefore, your answer should be: 74


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

3 0
1 year ago
Read 2 more answers
HElp me?<br> Please? Yikes?
Contact [7]

Answer:

A

Step-by-step explanation:

6 0
2 years ago
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What is the area of the rectangle? Round to the nearest square inch.
Mademuasel [1]
Asking the Math Gods...

A=W*L

9*3=27in^2
9*5=45in^2

3 0
3 years ago
What is the correct answer to this question?<br><br> F/2=5/8
ANTONII [103]

Answer:

F = 1.25

Step-by-step explanation:

All you would have to do is cross multiply, so our equations starts at \frac{F}{2} = \frac{5}{8}. We would now multiply F by 8 and 2 by 5. We now have 8F = 10. We can now divide both sides of the equation by 8 to get F = 1.25.

4 0
3 years ago
Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed
vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 11-1 = 10.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have T = 1.812

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{4}{\sqrt{11}} = 1.2060

Now, we multiply T and s

M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

L = 97 + 2.19 = 99.19 = 99.2cm

So

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0
3 years ago
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