Question

Find the value of each expression. Show your work. 9^P^3

Answer 1

$_n{P}_r = \frac{n!}{(n - r)!}$
$_9P_3 = \frac{9!}{(9 - 3)!}$
$_9P_3 = \frac{9!}{6!}$
$_9P_3 = \frac{9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1}{6 * 5 * 4 * 3 * 2* 1}$
$_9P_3 = 9 * 8 * 7$
$_9P_3 = 72 * 7$
$_9P_3 = 504$