Answer:
head of the humerus, Acromial end of the clavicle
Explanation:
The shoulder is made up of three bones: the scapula, the clavicle and the humerus (upper arm bone). Two joints in the shoulder allow it to move: the acromioclavicular joint, where the highest point of the scapula (acromion) meets the clavicle at its acromial end (the sternal end of the clavicle is bounded to the sternon), and the glenohumeral joint. The scapula also bounds to the head of the humerus, it is, the distal superior end.
They are two very different tunings. Urination is basically releasing your urine while the other one relates to releasing sperm..
Option (D) flagellated protist is correct.
The last common ancestor of all animals was probably a flagellated protist.
<h3>What is a Protist?</h3>
- Any eukaryotic organism that is not an animal, plant, or fungus is referred to as a protist.
- The absence of other eukaryotes means that protists do not constitute a natural group, or clade, even though it seems likely that they all descended from a common ancestor.
- Protozoa is another name for protists that resemble animals. Some are parasites as well.
- The four phyla that make up the Protozoa are flagellates, ciliates, spore-forming protists, and protists that resemble amoebas.
- Nuclear membranes surround the DNA of protists.
- Most protists are motile, or able to move, and many of them inhabit aquatic settings.
- Protists can reproduce sexually and/or asexually, and their life cycles are intricate.
- Protists consume, absorb, or produce food through photosynthesis.
Learn more about protist here:
brainly.com/question/1626285
#SPJ4
Answer:
No, the child cannot inherit the disease.
Explanation:
The problem tells you that the man has a recessive allele for an inherited disease, but he has a normal phenotype. This means that the disease is recessive and in order for an individual to have the disease, they must have two recessive copies of the allele. The problem also tells you that the mother has a genotype that does not include this allele. With this information, you can do a punnet cross of BB (mother) x Bb (carrier father), and end up with the following possible genotypes: BB, Bb, BB, Bb. Therefore the child will not have the disease, but there is a 50% chance that the child will be a carrier for the disease.
The term that is being referred to in the given item above is essential lipid which other may more fondly refer to as essential fatty acids. These essential substances are mostly needed for the maintenance and integrity of the cellular membranes to be able to do their functions.
